Principles Related to Practical Chemistry
1. Detection of Extra Elements
- Why a fusion step is needed: nitrogen, sulphur and the halogens in an organic compound are covalently bonded, so they give none of the ionic tests directly. Fusing the compound with a small piece of sodium metal converts them into ionic salts, NaCN, Na2S and NaX, which dissolve in water. The filtrate is the sodium fusion extract (Lassaigne's extract), and every test below is a test on these simple ions.
- Nitrogen: boil the extract with freshly prepared FeSO4, then acidify with dilute H2SO4. A Prussian blue colour, Fe4[Fe(CN)6]3, confirms nitrogen.
- Sulphur: sodium nitroprusside gives a purple colour (Na4[Fe(CN)5NOS]); or, after acidifying with acetic acid, lead acetate gives black PbS.
- Nitrogen and sulphur together: the extract contains NaSCN, which gives a blood-red colour with Fe3+, due to [Fe(SCN)]2+. No Prussian blue forms in this case.
- Halogens: boil the extract with dilute HNO3 (this destroys CN− and S2− as HCN and H2S) and then add AgNO3. AgCl is white and dissolves in dilute NH4OH; AgBr is pale yellow and only partly soluble; AgI is yellow and insoluble.
- Phosphorus: the compound is oxidised to phosphate, which gives a canary-yellow precipitate with ammonium molybdate in hot HNO3.
2. Functional Group Tests
- Unsaturation (C=C, C≡C): Br2 water or Br2 in CCl4 is decolourised; cold, dilute, alkaline KMnO4 (Baeyer's reagent) is also decolourised.
- Alcohol (–OH): sodium metal gives H2 gas. Lucas test (conc. HCl + anhydrous ZnCl2): tertiary alcohols give turbidity at once, secondary after about 5 minutes, primary none at room temperature. The rate follows carbocation stability.
- Phenol: neutral FeCl3 gives a violet, blue or green colour; bromine water gives a white precipitate of 2,4,6-tribromophenol.
- Aldehydes and ketones (C=O): 2,4-DNP (2,4-dinitrophenylhydrazine) gives a yellow-orange or red precipitate with BOTH.
- Only aldehydes reduce Tollens' reagent (silver mirror) and Fehling's solution (red-brown Cu2O). Benzaldehyde gives Tollens' but not Fehling's.
- Iodoform test: I2 + NaOH gives yellow CHI3 with CH3CO– compounds (methyl ketones, acetaldehyde) and CH3CH(OH)– compounds (ethanol, propan-2-ol).
- Carboxylic acids (–COOH): brisk effervescence of CO2 with NaHCO3; phenols do not give it.
- Primary amines: the carbylamine test (CHCl3 + alcoholic KOH, heat) gives a foul-smelling isocyanide. The azo dye test (aromatic primary amines): diazotise with NaNO2 + HCl at 273–278 K, then couple with alkaline 2-naphthol for an orange-red dye. The Hinsberg test (C6H5SO2Cl) separates primary (product dissolves in alkali), secondary (insoluble) and tertiary (no reaction) amines.
3. Preparations
- Mohr's salt, FeSO4·(NH4)2SO4·6H2O: equimolar FeSO4·7H2O and (NH4)2SO4 are dissolved in water containing dilute H2SO4, which stops hydrolysis of Fe2+ (and its oxidation to Fe3+). The solution is concentrated, cooled slowly and the pale green crystals are collected. It is a double salt, and it is a good primary standard for redox titrations because it is much less prone to air oxidation than plain FeSO4.
- Potash alum, K2SO4·Al2(SO4)3·24H2O: aluminium scrap dissolves in hot KOH to give K[Al(OH)4]; dilute H2SO4 is added to dissolve the Al(OH)3 that first precipitates, and the solution is concentrated and cooled to give colourless octahedral crystals.
- Acetanilide: aniline is acetylated with acetic anhydride (or glacial acetic acid), with zinc dust added to stop aniline oxidising to coloured products. The product is recrystallised from hot water or ethanol.
- p-Nitroacetanilide: acetanilide is nitrated with a nitrating mixture (conc. HNO3 + conc. H2SO4) below about 288 K. The acetyl group protects the –NH2 from oxidation and from protonation (which would give the meta product); the para isomer is major and the ortho isomer is the minor product, removed on recrystallisation from ethanol.
- Aniline yellow (p-aminoazobenzene): aniline is diazotised (NaNO2 + HCl, 273–278 K) and the diazonium salt is coupled with more aniline in weakly acidic medium to give a yellow azo dye.
- Iodoform: ethanol or acetone is warmed with I2 and NaOH (or NaOCl); a yellow precipitate of CHI3 with an antiseptic smell separates.
4. Titrimetric Exercises
- Principle: at the end point the equivalents of titrant equal the equivalents of analyte. For a reaction in which the n-factors are n1 and n2: n1M1V1 = n2M2V2. For acid-base reactions, N1V1 = N2V2 where N = n × M.
- A standard solution is one of accurately known concentration. A primary standard (oxalic acid dihydrate, anhydrous Na2CO3, Mohr's salt) can be weighed directly, because it is pure, stable and non-hygroscopic. NaOH and KMnO4 are not primary standards and must be standardised against one.
- Indicators for acid-base titrations:
- Phenolphthalein (pH range about 8.3–10): colourless in acid, pink in base. Use for strong acid vs strong base and weak acid vs strong base (for example oxalic acid vs NaOH).
- Methyl orange (pH range about 3.1–4.4): red in acid, yellow in base. Use for strong acid vs strong base and strong acid vs weak base (for example HCl vs Na2CO3).
- Weak acid vs weak base: no sharp indicator exists, because there is no steep change of pH near the end point.
- Oxalic acid vs KMnO4: 2MnO4− + 5C2O42− + 16H+ → 2Mn2+ + 10CO2 + 8H2O. The oxalic acid is warmed to 60–70 °C (the reaction is slow in the cold) in the presence of dilute H2SO4. KMnO4 is its own indicator: the end point is the first permanent light pink colour. The first few drops decolourise slowly, and then Mn2+ formed catalyses the reaction (autocatalysis), so it speeds up.
- Mohr's salt vs KMnO4: MnO4− + 5Fe2+ + 8H+ → Mn2+ + 5Fe3+ + 4H2O. This is done in the cold with dilute H2SO4; the n-factor of Mohr's salt is 1 (one Fe2+ per formula unit), that of oxalic acid is 2, and that of KMnO4 in acid is 5.
- Why only dilute H2SO4: HCl would be oxidised to Cl2 by KMnO4, and HNO3 is itself an oxidising agent that would oxidise the analyte. Dilute H2SO4 is neither oxidised nor oxidising. Without enough acid, KMnO4 goes only to brown MnO2.
- Worked example. 20 mL of 0.05 M oxalic acid needs 25 mL of KMnO4. Oxalic acid n = 2, KMnO4 n = 5. So 2 × 0.05 × 20 = 5 × M × 25, giving M = 2.0/125 = 0.016 M.
5. Qualitative Salt Analysis
- Preliminary tests: colour, smell and the flame test. A paste of the salt in conc. HCl is held on a platinum wire in the non-luminous flame. For coloured transition-metal ions the borax bead test is used.
Anions: tests with acids
- Dilute H2SO4 (or HCl) group: CO32− gives CO2, which turns lime water milky; S2− gives H2S with a rotten-egg smell, which blackens lead acetate paper; SO32− gives SO2, which turns acidified K2Cr2O7 green; NO2− gives reddish-brown NO2 fumes.
- Concentrated H2SO4 group: Cl− gives colourless HCl fumes (dense white fumes with NH3); Br− gives reddish-brown Br2 vapour; I− gives violet I2 vapour; NO3− gives brown fumes when heated with copper turnings.
Anions: confirmatory tests
- Cl−, Br−, I−: AgNO3 (with dilute HNO3) gives white (soluble in NH4OH), pale yellow (partly soluble) and yellow (insoluble) precipitates. Chromyl chloride test (for Cl− only): K2Cr2O7 + conc. H2SO4 gives red CrO2Cl2 vapours.
- SO42−: BaCl2 gives a white precipitate insoluble in dilute HCl.
- S2−: sodium nitroprusside gives a purple colour.
- NO3−: brown ring test. Fresh FeSO4 is added, then conc. H2SO4 is run slowly down the side of the test tube. A brown ring of [Fe(H2O)5NO]2+ forms at the junction of the two layers.
- NO2−: in acetic acid, FeSO4 gives a dark brown colour, and KI + starch turns blue.
Cations: the group scheme
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Group I (Pb2+): dilute HCl gives white PbCl2, soluble in hot water. Chromate: yellow PbCrO4. Iodide: yellow PbI2.
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Group II (Cu2+, Pb2+): H2S in presence of dilute HCl gives black CuS. Cu2+ gives a deep blue solution with excess NH4OH, chocolate-brown Cu2[Fe(CN)6] with K4[Fe(CN)6].
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Group III (Fe3+, Al3+): NH4OH in presence of NH4Cl gives reddish-brown Fe(OH)3 and white gelatinous Al(OH)3. Fe3+: Prussian blue with K4[Fe(CN)6], blood red with KSCN. Al3+: Al(OH)3 dissolves in excess NaOH, and the red lake with aluminon.
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Group IV (Zn2+, Ni2+, Co2+, Mn2+): H2S in ammoniacal medium. ZnS is white (dissolves in HCl), NiS and CoS are black (not soluble in dilute HCl once formed), MnS is buff. Ni2+ gives a red precipitate with dimethylglyoxime; Zn2+ gives a white or bluish-white precipitate with K4[Fe(CN)6]; Co2+ with KNO2 + CH3COOH gives yellow K3[Co(NO2)6].
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Group V (Ba2+, Ca2+, Sr2+): (NH4)2CO3 in presence of NH4Cl and NH4OH gives white carbonates. Ba2+ gives yellow BaCrO4 with K2CrO4; the flame colours (apple green, brick red, crimson) distinguish the three.
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Group VI (Mg2+): Na2HPO4 in NH4OH gives white crystalline Mg(NH4)PO4.
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Group 0 (NH4+): tested on the original salt. Warm with NaOH to liberate NH3 and detect it with Nessler's reagent (alkaline K2HgI4), which gives a brown precipitate or colour.
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Why the scheme works (solubility product): in Group II the HCl keeps [S2−] very low (common-ion effect), so only the sulphides with the smallest Ksp precipitate. In Group IV the ammoniacal medium removes H+, so [S2−] is high enough to precipitate the more soluble sulphides. In Group III, NH4Cl suppresses ionisation of NH4OH, lowering [OH−] so only the very insoluble hydroxides (Ksp about 10−38) precipitate. Before Group III, H2S is boiled off and a little conc. HNO3 is added to oxidise Fe2+ to Fe3+.
6. Enthalpy, Sols and Kinetics Experiments
- Enthalpy of solution of CuSO4: a known mass of CuSO4 is dissolved in a known volume of water in a calorimeter (an insulated vessel). From the temperature change, q = m × s × ΔT and ΔsolH = −q / (moles of solute). Anhydrous CuSO4 dissolves exothermically, while CuSO4·5H2O dissolves slightly endothermically.
- Enthalpy of neutralisation: equal volumes of strong acid and strong base of the same concentration are mixed in the calorimeter. For HCl and NaOH, ΔneutH is about −57 kJ mol−1, because the net reaction is only H+ + OH− → H2O. A weak acid or weak base gives a less negative value, because some energy goes into ionising it.
- Lyophilic and lyophobic sols: a lyophilic (solvent-loving) sol such as starch, gum or egg albumin forms simply by dissolving in water and is stable, reversible, and not easily coagulated. A lyophobic sol such as ferric hydroxide is made by adding FeCl3 drop by drop to boiling water (hydrolysis gives a reddish-brown Fe(OH)3 sol); it is unstable, irreversible and coagulated by a small amount of electrolyte. As2S3 sol and sulphur sol are other examples.
- Kinetics of I− + H2O2: H2O2 + 2I− + 2H+ → I2 + 2H2O. The rate is found from the time taken for a fixed amount of I2 to appear, detected by a starch blue colour after a known small amount of Na2S2O3 has been consumed (a clock reaction). The rate is first order in each of H2O2 and I−; the reaction is therefore overall second order.
7. How NEET Frames These Questions
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Single-fact recall: most NEET questions here are one-line facts: which acid goes into Mohr's salt, which group a cation belongs to, which reaction is NOT part of Lassaigne's test, which colour the indicator shows. Learn the facts in the tables above exactly as written.
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Matching and ordering: the group-number questions come as "arrange in increasing group number" or "match the ion with its group". Memorise the one-line list of groups and read the options for the one that fits every row.
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Statement questions: Lucas test is the classic: the traps are the rates for primary versus tertiary alcohols.
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Calculation: at most one short numerical, such as pH from a solubility-product constant of a hydroxide, or an n-factor titration. Write the equation, plug in, and check the final step (pH = 14 − pOH).
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Quick checklist before the exam:
- Colours: Prussian blue (N), purple (S), blood red (N + S), white / pale yellow / yellow AgX, brown ring (NO3−), chocolate brown Cu2[Fe(CN)6], buff MnS.
- Group order and group reagents, with the cations in each group.
- Why dilute H2SO4 is used in Mohr's salt preparation and in KMnO4 titrations, and why HCl and HNO3 are not.
- Indicator for each type of acid-base titration, and the direction of the colour change.
- n-factors: KMnO4 = 5, oxalic acid = 2, Mohr's salt = 1.