Organic Compounds Containing Nitrogen (Amines & Diazonium Salts)
Organic Chemistry
Weightage: 2–3 Questions (8–12 Marks)
NMC Unit 18
“Amines and diazonium salts govern the nitrogenous chemistry of pharmaceuticals, synthetic fibres, and azo dyes. From the gas vs aqueous basicity paradox and Gabriel phthalimide selectivity to Hinsberg differentiation and diazonium coupling pathways, this chapter secures 8 to 12 marks in NEET Organic Chemistry.”
— SCORECHEM ACADEMIC TEAM
1. Structure, Classification & Nomenclature
Electronic Geometry: Nitrogen is s p 3 sp^3 s p 3 -hybridised with a trigonal pyramidal shape. The unshared electron pair occupies the fourth hybrid orbital, compressing the C − N − C \text{C}-\text{N}-\text{C} C − N − C bond angle to 108 ∘ 108^\circ 10 8 ∘ (e.g., trimethylamine) due to lone pair-bond pair repulsion.
Classification Framework:
Primary (1 ∘ 1^\circ 1 ∘ ): One hydrogen of ammonia replaced by an alkyl/aryl group (R − NH 2 \text{R}-\text{NH}_2 R − NH 2 ).
Secondary (2 ∘ 2^\circ 2 ∘ ): Two hydrogens replaced (R 2 NH \text{R}_2\text{NH} R 2 NH or R − NH − R ′ \text{R}-\text{NH}-\text{R}' R − NH − R ′ ).
Tertiary (3 ∘ 3^\circ 3 ∘ ): All three hydrogens replaced (R 3 N \text{R}_3\text{N} R 3 N ).
Quaternary Ammonium Salts: Tetra-alkylated nitrogen cations (R 4 N + X − \text{R}_4\text{N}^+\text{X}^- R 4 N + X − ) used as cationic surfactants.
IUPAC Nomenclature: Aliphatic amines are named as alkanamines by replacing the final 'e' of the alkane name with 'amine' (e.g., CH 3 CH 2 NH 2 \text{CH}_3\text{CH}_2\text{NH}_2 CH 3 CH 2 NH 2 is ethanamine). In secondary and tertiary amines, substituents on nitrogen take the locant prefix N N N (e.g., N N N -methylethanamine, N , N N,N N , N -dimethylaniline).
2. Preparative Routes: Reduction, Gabriel & Hoffmann
Reduction of Nitrogenous Precursors:
Nitro Compounds: Catalytic hydrogenation over Pd / Pt \text{Pd}/\text{Pt} Pd / Pt or reduction with metals in acid:
Ar-NO 2 + 3 Fe + 6 HCl ⟶ Ar-NH 2 + 3 FeCl 2 + 2 H 2 O \text{Ar-NO}_2 + 3\text{Fe} + 6\text{HCl} \longrightarrow \text{Ar-NH}_2 + 3\text{FeCl}_2 + 2\text{H}_2\text{O}
Ar-NO 2 + 3 Fe + 6 HCl ⟶ Ar-NH 2 + 3 FeCl 2 + 2 H 2 O
Fe + HCl \text{Fe} + \text{HCl} Fe + HCl is preferred industrially because the generated FeCl 2 \text{FeCl}_2 FeCl 2 hydrolyses to regenerate HCl \text{HCl} HCl , requiring only catalytic acid initiation.
Nitriles (Mendius Reduction): Reduction with LiAlH 4 \text{LiAlH}_4 LiAlH 4 or Na(Hg) / EtOH \text{Na(Hg)}/\text{EtOH} Na(Hg) / EtOH yields primary amines with one additional carbon:
R-C ≡ N → LiAlH 4 R-CH 2 − NH 2 \text{R-C}\equiv\text{N} \xrightarrow{\text{LiAlH}_4} \text{R-CH}_2-\text{NH}_2
R-C ≡ N LiAlH 4 R-CH 2 − NH 2
Amides: R-CONH 2 → (i) LiAlH 4 , (ii) H 2 O R-CH 2 − NH 2 \text{R-CONH}_2 \xrightarrow{\text{(i) }\text{LiAlH}_4\text{, (ii) }\text{H}_2\text{O}} \text{R-CH}_2-\text{NH}_2 R-CONH 2 (i) LiAlH 4 , (ii) H 2 O R-CH 2 − NH 2 .
Gabriel Phthalimide Synthesis: Potassium phthalimide undergoes nucleophilic S N 2 \text{S}_\text{N}2 S N 2 displacement with primary alkyl halides, followed by alkaline hydrolysis to yield pure primary aliphatic amines:
Phthalimide → KOH Potassium Phthalimide → R-X N -Alkylphthalimide → aq. NaOH Sodium Phthalate + R-NH 2 \text{Phthalimide} \xrightarrow{\text{KOH}} \text{Potassium Phthalimide} \xrightarrow{\text{R-X}} N\text{-Alkylphthalimide} \xrightarrow{\text{aq. NaOH}} \text{Sodium Phthalate} + \text{R-NH}_2
Phthalimide KOH Potassium Phthalimide R-X N -Alkylphthalimide aq. NaOH Sodium Phthalate + R-NH 2
Aromatic primary amines cannot be prepared this way because aryl halides resist nucleophilic substitution by the phthalimide anion.
Hoffmann Bromamide Degradation: Primary amides react with bromine in aqueous or ethanolic NaOH \text{NaOH} NaOH to yield primary amines with one less carbon atom:
R-CONH 2 + Br 2 + 4 NaOH ⟶ R-NH 2 + Na 2 CO 3 + 2 NaBr + 2 H 2 O \text{R-CONH}_2 + \text{Br}_2 + 4\text{NaOH} \longrightarrow \text{R-NH}_2 + \text{Na}_2\text{CO}_3 + 2\text{NaBr} + 2\text{H}_2\text{O}
R-CONH 2 + Br 2 + 4 NaOH ⟶ R-NH 2 + Na 2 CO 3 + 2 NaBr + 2 H 2 O
3. Physical Properties & The Basicity Paradox
Physical State & Boiling Points: Lower aliphatic amines are gases with a fishy odour. Boiling points follow the order: 1 ∘ Amine > 2 ∘ Amine > 3 ∘ Amine 1^\circ\text{ Amine} > 2^\circ\text{ Amine} > 3^\circ\text{ Amine} 1 ∘ Amine > 2 ∘ Amine > 3 ∘ Amine , because 1 ∘ 1^\circ 1 ∘ amines form two intermolecular hydrogen bonds, 2 ∘ 2^\circ 2 ∘ form one, and 3 ∘ 3^\circ 3 ∘ amines lack N − H \text{N}-\text{H} N − H bonds entirely.
Gas Phase Basicity: In the absence of solvent, basic strength is governed entirely by the + I +I + I inductive electron push of alkyl groups:
Gas Phase: 3 ∘ Amine > 2 ∘ Amine > 1 ∘ Amine > NH 3 \text{Gas Phase: } 3^\circ\text{ Amine} > 2^\circ\text{ Amine} > 1^\circ\text{ Amine} > \text{NH}_3
Gas Phase: 3 ∘ Amine > 2 ∘ Amine > 1 ∘ Amine > NH 3
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Basicity Dynamics: Gas Phase (+I Effect) vs Aqueous Phase (Solvation + Steric)
Gas Phase (Pure Inductive Effect)
3° > 2° > 1° > NH₃
No solvent interaction or hydration;
Governed strictly by +I electron push
Aqueous Phase (Subtle Interplay)
Ethyl Series: 2° > 3° > 1° > NH₃
(Et₂NH > Et₃N > EtNH₂ > NH₃)
Methyl Series: 2° > 1° > 3° > NH₃
(Me₂NH > MeNH₂ > Me₃N > NH₃)
Figure 18.1: Basicity Dynamics: Gas Phase Inductive Influence vs Aqueous Interplay
Aqueous Phase Basicity Paradox: In water, basicity is governed by an interplay of three opposing factors: inductive effect (+ I +I + I ), steric hindrance, and stabilization of the conjugate ammonium cation by hydrogen-bonded solvation:
Ethyl series: ( C 2 H 5 ) 2 NH > ( C 2 H 5 ) 3 N > C 2 H 5 NH 2 > NH 3 (\text{C}_2\text{H}_5)_2\text{NH} > (\text{C}_2\text{H}_5)_3\text{N} > \text{C}_2\text{H}_5\text{NH}_2 > \text{NH}_3 ( C 2 H 5 ) 2 NH > ( C 2 H 5 ) 3 N > C 2 H 5 NH 2 > NH 3 (2 ∘ > 3 ∘ > 1 ∘ > NH 3 2^\circ > 3^\circ > 1^\circ > \text{NH}_3 2 ∘ > 3 ∘ > 1 ∘ > NH 3 ).
Methyl series: ( CH 3 ) 2 NH > CH 3 NH 2 > ( CH 3 ) 3 N > NH 3 (\text{CH}_3)_2\text{NH} > \text{CH}_3\text{NH}_2 > (\text{CH}_3)_3\text{N} > \text{NH}_3 ( CH 3 ) 2 NH > CH 3 NH 2 > ( CH 3 ) 3 N > NH 3 (2 ∘ > 1 ∘ > 3 ∘ > NH 3 2^\circ > 1^\circ > 3^\circ > \text{NH}_3 2 ∘ > 1 ∘ > 3 ∘ > NH 3 ).
Arylamines Basicity: Aniline (p K b = 9.38 \text{p}K_b = 9.38 p K b = 9.38 ) is weaker than ammonia (p K b = 4.75 \text{p}K_b = 4.75 p K b = 4.75 ) due to resonance delocalization of the nitrogen lone pair into the ring. Electron-donating groups (− OCH 3 , − CH 3 -\text{OCH}_3, -\text{CH}_3 − OCH 3 , − CH 3 ) increase basicity, whereas electron-withdrawing groups (− NO 2 , − CN , − X -\text{NO}_2, -\text{CN}, -\text{X} − NO 2 , − CN , − X ) decrease it.
4. Chemical Reactions: Acylation & Carbylamine Test
Acylation & Benzoylation (Schotten-Baumann Reaction): Primary and secondary amines react with acid chlorides or anhydrides in the presence of pyridine to form substituted amides. Pyridine removes the formed HCl \text{HCl} HCl , driving equilibrium forward:
C 2 H 5 NH 2 + CH 3 COCl → Pyridine C 2 H 5 NHCOCH 3 + HCl \text{C}_2\text{H}_5\text{NH}_2 + \text{CH}_3\text{COCl} \xrightarrow{\text{Pyridine}} \text{C}_2\text{H}_5\text{NHCOCH}_3 + \text{HCl}
C 2 H 5 NH 2 + CH 3 COCl Pyridine C 2 H 5 NHCOCH 3 + HCl
Carbylamine Test (Isocyanide Test for 1 ∘ 1^\circ 1 ∘ Amines): Primary aliphatic and aromatic amines on heating with chloroform and ethanolic KOH \text{KOH} KOH produce foul-smelling isocyanides:
R-NH 2 + CHCl 3 + 3 KOH → Δ R-NC ( Carbylamine ) + 3 KCl + 3 H 2 O \text{R-NH}_2 + \text{CHCl}_3 + 3\text{KOH} \xrightarrow{\Delta} \text{R-NC}\ (\text{Carbylamine}) + 3\text{KCl} + 3\text{H}_2\text{O}
R-NH 2 + CHCl 3 + 3 KOH Δ R-NC ( Carbylamine ) + 3 KCl + 3 H 2 O
Secondary and tertiary amines do not undergo this reaction.
5. Hinsberg Test & Nitrous Acid Differentiation
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Hinsberg Reagent (Ph-SO₂Cl) Differentiation of 1°, 2°, and 3° Amines
1° Amine (R-NH₂)
Forms Ph-SO₂-NH-R
(Has acidic N-H proton)
SOLUBLE IN KOH
2° Amine (R₂NH)
Forms Ph-SO₂-NR₂
(No acidic hydrogen)
INSOLUBLE IN KOH
3° Amine (R₃N)
No replaceable H on N
NO REACTION
Figure 18.2: Hinsberg Reagent Differentiation of Primary, Secondary, and Tertiary Amines
Hinsberg Reagent (C 6 H 5 SO 2 Cl \text{C}_6\text{H}_5\text{SO}_2\text{Cl} C 6 H 5 SO 2 Cl ):
Primary Amines: Form N N N -alkylbenzenesulphonamide, which contains an acidic hydrogen on nitrogen and dissolves in aqueous KOH \text{KOH} KOH .
Secondary Amines: Form N , N N,N N , N -dialkylbenzenesulphonamide, which lacks an acidic hydrogen and remains insoluble in alkali.
Tertiary Amines: Do not react under Hinsberg conditions.
Reaction with Nitrous Acid (HNO 2 \text{HNO}_2 HNO 2 generated in situ):
Primary Aliphatic Amines: Form highly unstable alkyldiazonium salts that decompose into alcohols, alkenes, and alkyl halides, liberating nitrogen gas quantitatively:
R-NH 2 + HNO 2 → NaNO 2 + HCl [ R-N 2 + Cl − ] → H 2 O R-OH + N 2 ↑ + HCl \text{R-NH}_2 + \text{HNO}_2 \xrightarrow{\text{NaNO}_2 + \text{HCl}} [\text{R-N}_2^+\text{Cl}^-] \xrightarrow{\text{H}_2\text{O}} \text{R-OH} + \text{N}_2\uparrow + \text{HCl}
R-NH 2 + HNO 2 NaNO 2 + HCl [ R-N 2 + Cl − ] H 2 O R-OH + N 2 ↑ + HCl
Primary Aromatic Amines: Form stable arenediazonium salts at low temperatures (273-278 K).
Secondary Amines: Form yellow oily N N N -nitrosamines.
6. Ring Electrophilic Substitutions of Aniline
Halogenation: Due to the strong activation of the − NH 2 -\text{NH}_2 − NH 2 group, aniline reacts with bromine water at room temperature to give an immediate white precipitate of 2,4,6-tribromoaniline:
C 6 H 5 NH 2 + 3 Br 2 ( aq ) ⟶ 2,4,6-Tribromoaniline ↓ + 3 HBr \text{C}_6\text{H}_5\text{NH}_2 + 3\text{Br}_2\ (\text{aq}) \longrightarrow \text{2,4,6-Tribromoaniline}\downarrow + 3\text{HBr}
C 6 H 5 NH 2 + 3 Br 2 ( aq ) ⟶ 2,4,6-Tribromoaniline ↓ + 3 HBr
To obtain monobromoaniline, the amino group must be protected by acetylation with acetic anhydride before bromination, followed by ester/amide hydrolysis.
Nitration: Direct nitration yields a mixture of products: 51 % p -nitroaniline 51\%\ p\text{-nitroaniline} 51% p -nitroaniline , 47 % m -nitroaniline 47\%\ m\text{-nitroaniline} 47% m -nitroaniline , and 2 % o -nitroaniline 2\%\ o\text{-nitroaniline} 2% o -nitroaniline . The high meta yield is due to protonation of aniline in strong acid to form the meta-directing anilinium ion.
Sulphonation: Heating anilinium hydrogensulphate at 453-473 K gives sulphanilic acid, which exists as a dipolar zwitterion:
C 6 H 5 NH 2 + conc. H 2 SO 4 ⟶ C 6 H 5 NH 3 + HSO 4 − → 453 − 473 K p -H 3 N + − C 6 H 4 − SO 3 − ( Zwitterion ) \text{C}_6\text{H}_5\text{NH}_2 + \text{conc. H}_2\text{SO}_4 \longrightarrow \text{C}_6\text{H}_5\text{NH}_3^+\text{HSO}_4^- \xrightarrow{453-473\text{ K}} p\text{-H}_3\text{N}^+-\text{C}_6\text{H}_4-\text{SO}_3^-\ (\text{Zwitterion})
C 6 H 5 NH 2 + conc. H 2 SO 4 ⟶ C 6 H 5 NH 3 + HSO 4 − 453 − 473 K p -H 3 N + − C 6 H 4 − SO 3 − ( Zwitterion )
7. Diazonium Salts: Preparation & Synthetic Hub
Diazotisation Mechanism: Primary aromatic amines react with NaNO 2 + 2 HCl \text{NaNO}_2 + 2\text{HCl} NaNO 2 + 2 HCl at 273-278 K (0 − 5 ∘ C 0-5^\circ\text{C} 0 − 5 ∘ C ) to form benzenediazonium chloride:
C 6 H 5 NH 2 + NaNO 2 + 2 HCl → 273 − 278 K C 6 H 5 N 2 + Cl − + NaCl + 2 H 2 O \text{C}_6\text{H}_5\text{NH}_2 + \text{NaNO}_2 + 2\text{HCl} \xrightarrow{273-278\text{ K}} \text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{NaCl} + 2\text{H}_2\text{O}
C 6 H 5 NH 2 + NaNO 2 + 2 HCl 273 − 278 K C 6 H 5 N 2 + Cl − + NaCl + 2 H 2 O
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Arenediazonium Salt (Ar-N₂⁺Cl⁻): Synthetic Hub for Aromatic Conversions
Ar-N₂⁺ Cl⁻
(273 - 278 K)
Ar-Cl / Ar-Br
Cu₂X₂ / HX (Sandmeyer)
Ar-F
HBF₄, Δ (Schiemann)
Ar-I
Warm aq. KI
Ar-H
H₃PO₂ or EtOH
Ar-OH
H₂O, warm > 283 K
Azo Dye (Ar-N=N-Ar')
Phenol (pH 9-10)
Aniline (pH 4-5)
Figure 18.3: Arenediazonium Chloride Synthetic Hub for Aromatic Conversions
Displacement Reactions of Nitrogen:
Sandmeyer Reaction: Ar-N 2 + Cl − → Cu 2 X 2 / HX Ar-X + N 2 ↑ ( X = Cl, Br, CN ) \text{Ar-N}_2^+\text{Cl}^- \xrightarrow{\text{Cu}_2\text{X}_2/\text{HX}} \text{Ar-X} + \text{N}_2\uparrow \quad (\text{X} = \text{Cl, Br, CN}) Ar-N 2 + Cl − Cu 2 X 2 / HX Ar-X + N 2 ↑ ( X = Cl, Br, CN ) .
Gattermann Reaction: Ar-N 2 + Cl − → Cu / HX Ar-X + N 2 ↑ + CuCl \text{Ar-N}_2^+\text{Cl}^- \xrightarrow{\text{Cu}/\text{HX}} \text{Ar-X} + \text{N}_2\uparrow + \text{CuCl} Ar-N 2 + Cl − Cu / HX Ar-X + N 2 ↑ + CuCl .
Iodination: Ar-N 2 + Cl − + KI ( warm ) ⟶ Ar-I + KCl + N 2 ↑ \text{Ar-N}_2^+\text{Cl}^- + \text{KI}\ (\text{warm}) \longrightarrow \text{Ar-I} + \text{KCl} + \text{N}_2\uparrow Ar-N 2 + Cl − + KI ( warm ) ⟶ Ar-I + KCl + N 2 ↑ .
Balz-Schiemann Reaction: Ar-N 2 + Cl − + HBF 4 ⟶ Ar-N 2 + BF 4 − → Δ Ar-F + BF 3 + N 2 ↑ \text{Ar-N}_2^+\text{Cl}^- + \text{HBF}_4 \longrightarrow \text{Ar-N}_2^+\text{BF}_4^- \xrightarrow{\Delta} \text{Ar-F} + \text{BF}_3 + \text{N}_2\uparrow Ar-N 2 + Cl − + HBF 4 ⟶ Ar-N 2 + BF 4 − Δ Ar-F + BF 3 + N 2 ↑ .
Deamination: Ar-N 2 + Cl − + H 3 PO 2 + H 2 O ⟶ Ar-H + N 2 ↑ + H 3 PO 3 + HCl \text{Ar-N}_2^+\text{Cl}^- + \text{H}_3\text{PO}_2 + \text{H}_2\text{O} \longrightarrow \text{Ar-H} + \text{N}_2\uparrow + \text{H}_3\text{PO}_3 + \text{HCl} Ar-N 2 + Cl − + H 3 PO 2 + H 2 O ⟶ Ar-H + N 2 ↑ + H 3 PO 3 + HCl .
Hydrolysis: Warming with water above 283 K forms phenol: Ar-N 2 + Cl − + H 2 O ⟶ Ar-OH + N 2 ↑ + HCl \text{Ar-N}_2^+\text{Cl}^- + \text{H}_2\text{O} \longrightarrow \text{Ar-OH} + \text{N}_2\uparrow + \text{HCl} Ar-N 2 + Cl − + H 2 O ⟶ Ar-OH + N 2 ↑ + HCl .
Azo Coupling Reactions: Diazonium salts act as electrophiles and couple with activated aromatic compounds:
With Phenol (mildly alkaline, pH 9 − 10 \text{pH } 9-10 pH 9 − 10 ): Yields p p p -hydroxyazobenzene (orange dye).
With Aniline (mildly acidic, pH 4 − 5 \text{pH } 4-5 pH 4 − 5 ): Yields p p p -aminoazobenzene (yellow dye).