Oxygen Derivatives: Alcohols, Phenols, Ethers, Carbonyls & Carboxylic Acids
Organic Chemistry
Weightage: 5–6 Questions (20–24 Marks)
NMC Unit 17
“Oxygen chemistry dominates the organic section of NEET. From Lucas turbidity kinetics and phenoxide Kolbe carboxylations to tetrahedral carbonyl additions, aldol condensations, haloform cleavages, and carboxyl resonance thermodynamics, this comprehensive master unit secures 20 to 24 marks.”
— SCORECHEM ACADEMIC TEAM
1. Alcohols & Phenols: Classification & C-O/O-H Polarity
Classification Framework:
Alcohols (s p 3 C-OH sp^3\text{ C-OH} s p 3 C-OH ): Primary (1 ∘ 1^\circ 1 ∘ ), secondary (2 ∘ 2^\circ 2 ∘ ), and tertiary (3 ∘ 3^\circ 3 ∘ ) based on alpha-carbon substitution. Allylic (CH 2 = CH − CH 2 OH \text{CH}_2=\text{CH}-\text{CH}_2\text{OH} CH 2 = CH − CH 2 OH ) and benzylic (Ar − CH 2 OH \text{Ar}-\text{CH}_2\text{OH} Ar − CH 2 OH ) alcohols can be 1 ∘ , 2 ∘ 1^\circ, 2^\circ 1 ∘ , 2 ∘ , or 3 ∘ 3^\circ 3 ∘ .
Vinylic Alcohols (s p 2 C-OH sp^2\text{ C-OH} s p 2 C-OH ): Hydroxyl group directly attached to an alkene carbon (CH 2 = CH − OH \text{CH}_2=\text{CH}-\text{OH} CH 2 = CH − OH ).
Phenols (s p 2 C-OH sp^2\text{ C-OH} s p 2 C-OH ): Hydroxyl group bonded directly to an aromatic ring.
Bond Geometries & Physical Constants:
Methanol C − O − H \text{C}-\text{O}-\text{H} C − O − H angle is 108.9 ∘ 108.9^\circ 108. 9 ∘ (compressed from 109.5 ∘ 109.5^\circ 109. 5 ∘ due to oxygen lone-pair repulsions).
Phenol C − O \text{C}-\text{O} C − O bond length is 136 pm 136\text{ pm} 136 pm versus 142 pm 142\text{ pm} 142 pm in methanol, shortened by resonance delocalization of oxygen lone pairs and s p 2 sp^2 s p 2 carbon hybridization.
Boiling points follow: Carboxylic Acids > Alcohols > Aldehydes/Ketones > Ethers > Alkanes \text{Carboxylic Acids} > \text{Alcohols} > \text{Aldehydes/Ketones} > \text{Ethers} > \text{Alkanes} Carboxylic Acids > Alcohols > Aldehydes/Ketones > Ethers > Alkanes .
Boiling points decrease with branching due to spherical surface minimization: Butan-1-ol ( 390 K ) > Butan-2-ol ( 373 K ) > 2-Methylpropan-2-ol ( 356 K ) \text{Butan-1-ol}\ (390\text{ K}) > \text{Butan-2-ol}\ (373\text{ K}) > \text{2-Methylpropan-2-ol}\ (356\text{ K}) Butan-1-ol ( 390 K ) > Butan-2-ol ( 373 K ) > 2-Methylpropan-2-ol ( 356 K ) .
2. Preparative Routes & Lucas Distinction
Hydration Pathways of Alkenes:
Acid-Catalyzed Hydration: Reversible Markovnikov addition via free carbocation intermediate susceptible to rearrangements.
Hydroboration-Oxidation: Syn-addition of diborane followed by alkaline H 2 O 2 \text{H}_2\text{O}_2 H 2 O 2 yields net anti-Markovnikov hydration product without rearrangement:
3 R-CH = CH 2 + 1 2 ( BH 3 ) 2 ⟶ ( R-CH 2 − CH 2 ) 3 B → H 2 O 2 , OH − 3 R-CH 2 − CH 2 OH + B(OH) 3 3\text{R-CH}=\text{CH}_2 + \frac{1}{2}(\text{BH}_3)_2 \longrightarrow (\text{R-CH}_2-\text{CH}_2)_3\text{B} \xrightarrow{\text{H}_2\text{O}_2,\ \text{OH}^-} 3\text{R-CH}_2-\text{CH}_2\text{OH} + \text{B(OH)}_3
3 R-CH = CH 2 + 2 1 ( BH 3 ) 2 ⟶ ( R-CH 2 − CH 2 ) 3 B H 2 O 2 , OH − 3 R-CH 2 − CH 2 OH + B(OH) 3
Reduction of Carbonyl Compounds:
NaBH 4 \text{NaBH}_4 NaBH 4 reduces aldehydes to 1 ∘ 1^\circ 1 ∘ alcohols and ketones to 2 ∘ 2^\circ 2 ∘ alcohols, leaving esters and acids unaffected.
LiAlH 4 \text{LiAlH}_4 LiAlH 4 reduces aldehydes, ketones, esters, and carboxylic acids to alcohols.
Grignard Addition to Carbonyls:
HCHO + RMgX → H 3 O + 1 ∘ Alcohol \text{HCHO} + \text{RMgX} \xrightarrow{\text{H}_3\text{O}^+} 1^\circ\text{ Alcohol} HCHO + RMgX H 3 O + 1 ∘ Alcohol
R’CHO + RMgX → H 3 O + 2 ∘ Alcohol \text{R'CHO} + \text{RMgX} \xrightarrow{\text{H}_3\text{O}^+} 2^\circ\text{ Alcohol} R’CHO + RMgX H 3 O + 2 ∘ Alcohol
R’COR” + RMgX → H 3 O + 3 ∘ Alcohol \text{R'COR''} + \text{RMgX} \xrightarrow{\text{H}_3\text{O}^+} 3^\circ\text{ Alcohol} R’COR” + RMgX H 3 O + 3 ∘ Alcohol
Lucas Distinction Reagent (conc. HCl + anhyd. ZnCl 2 \text{conc. HCl} + \text{anhyd. ZnCl}_2 conc. HCl + anhyd. ZnCl 2 ):
R-OH + HCl → ZnCl 2 R-Cl ↓ ( Turbidity ) + H 2 O \text{R-OH} + \text{HCl} \xrightarrow{\text{ZnCl}_2} \text{R-Cl}\downarrow (\text{Turbidity}) + \text{H}_2\text{O}
R-OH + HCl ZnCl 2 R-Cl ↓ ( Turbidity ) + H 2 O
3 ∘ 3^\circ 3 ∘ Alcohols: Turbidity appears immediately.
2 ∘ 2^\circ 2 ∘ Alcohols: Turbidity appears within 5 minutes.
1 ∘ 1^\circ 1 ∘ Alcohols: Solution remains clear at room temperature; requires heating.
3. Phenols: Acidity, Kolbe & Reimer-Tiemann
Acidity Hierarchy:
Electron-withdrawing groups (− M , − I -M, -I − M , − I ) stabilize the phenoxide anion and increase acidity (o / p -NO 2 > m -NO 2 > Phenol > Cresols o/p\text{-NO}_2 > m\text{-NO}_2 > \text{Phenol} > \text{Cresols} o / p -NO 2 > m -NO 2 > Phenol > Cresols ).
p K a metrics: 2,4,6-trinitrophenol (picric acid, 0.38) < 4 -nitrophenol (7.1) < 2 -nitrophenol (7.2) < phenol (10.0) < ethanol (15.9) \text{p}K_a\text{ metrics: 2,4,6-trinitrophenol (picric acid, 0.38)} < 4\text{-nitrophenol (7.1)} < 2\text{-nitrophenol (7.2)} < \text{phenol (10.0)} < \text{ethanol (15.9)} p K a metrics: 2,4,6-trinitrophenol (picric acid, 0.38) < 4 -nitrophenol (7.1) < 2 -nitrophenol (7.2) < phenol (10.0) < ethanol (15.9) .
Electrophilic Substitution of Phenol: Reimer-Tiemann vs Kolbe Reactions
OH
Phenol
1. CHCl₃ + NaOH
2. H⁺ (:CCl₂ attack)
OH
CHO
Salicylaldehyde
(Reimer-Tiemann)
1. CO₂ + NaOH (400 K)
2. H⁺ (Electrophile CO₂)
OH
COOH
Salicylic Acid
(Kolbe's Product)
Figure 17.1: Electrophilic Aromatic Substitutions of Phenol via Phenoxide Activation
Industrial Synthesis from Cumene:
Cumene (isopropylbenzene) is oxidized with air to cumene hydroperoxide, then cleaved with dilute H 2 SO 4 \text{H}_2\text{SO}_4 H 2 SO 4 to yield phenol and acetone.
Kolbe Reaction: Sodium phenoxide reacts with CO 2 \text{CO}_2 CO 2 at 400 K and 4-7 atm followed by acidification to produce salicylic acid (2-hydroxybenzoic acid).
Reimer-Tiemann Reaction: Phenol reacts with CHCl 3 \text{CHCl}_3 CHCl 3 and aqueous NaOH \text{NaOH} NaOH through a dichlorocarbene intermediate (: CCl 2 :\text{CCl}_2 : CCl 2 ) to form salicylaldehyde.
4. Ethers: Williamson Synthesis & Acidic Cleavage
Williamson Ether Synthesis:
R-X + R’-O − Na + ⟶ R-O-R’ + NaX \text{R-X} + \text{R'-O}^-\text{Na}^+ \longrightarrow \text{R-O-R'} + \text{NaX}
R-X + R’-O − Na + ⟶ R-O-R’ + NaX
Alkyl halide must be primary (1 ∘ 1^\circ 1 ∘ ). Secondary and tertiary halides undergo E2 elimination to yield alkenes as the major or exclusive product.
Acidic Cleavage with Concentrated Hydrogen Halides (HI > HBr \text{HI} > \text{HBr} HI > HBr ):
Primary / Secondary Alkyl Groups ( S N 2 \text{S}_\text{N}2 S N 2 ): Iodide attacks the less hindered alkyl carbon to yield lower alkyl iodide and higher alcohol:
CH 3 -O-CH(CH 3 ) 2 + HI ⟶ CH 3 I + ( CH 3 ) 2 CHOH \text{CH}_3\text{-O-CH(CH}_3)_2 + \text{HI} \longrightarrow \text{CH}_3\text{I} + (\text{CH}_3)_2\text{CHOH}
CH 3 -O-CH(CH 3 ) 2 + HI ⟶ CH 3 I + ( CH 3 ) 2 CHOH
Tertiary Alkyl Group Present ( S N 1 \text{S}_\text{N}1 S N 1 ): Cleavage proceeds via a stable tertiary carbocation to yield tertiary iodide:
( CH 3 ) 3 C-O-CH 3 + HI ⟶ ( CH 3 ) 3 C-I + CH 3 OH (\text{CH}_3)_3\text{C-O-CH}_3 + \text{HI} \longrightarrow (\text{CH}_3)_3\text{C-I} + \text{CH}_3\text{OH}
( CH 3 ) 3 C-O-CH 3 + HI ⟶ ( CH 3 ) 3 C-I + CH 3 OH
Alkyl Aryl Ethers (Anisole): Protonation forms an oxonium ion; iodide attacks the methyl carbon because the s p 2 sp^2 s p 2 phenyl-oxygen bond has partial double bond character and resists attack:
C 6 H 5 -O-CH 3 + HI ⟶ C 6 H 5 OH + CH 3 I \text{C}_6\text{H}_5\text{-O-CH}_3 + \text{HI} \longrightarrow \text{C}_6\text{H}_5\text{OH} + \text{CH}_3\text{I}
C 6 H 5 -O-CH 3 + HI ⟶ C 6 H 5 OH + CH 3 I
5. Carbonyls: Nucleophilic Addition Dynamics
Planar Carbonyl Geometry: The carbonyl carbon is s p 2 sp^2 s p 2 -hybridized, planar, and electrophilic due to polarization (C δ + = O δ − \text{C}^{\delta+} = \text{O}^{\delta-} C δ + = O δ − ). Nucleophiles attack perpendicular to the plane at approximately 107 ∘ 107^\circ 10 7 ∘ (Bürgi-Dunitz angle).
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Mechanism of Nucleophilic Addition to Planar Carbonyl Group (>C=O)
Nu⁻
C
O
R
H (or R')
sp² (Trigonal Planar, 120°)
Slow (r.d.s)
C
O⁻
Nu
R
sp³ Intermediate
+ H⁺ (Fast)
C
OH
Nu
Addition Product
Figure 17.2: Two-Step Nucleophilic Addition Across the Polarized Trigonal Planar Carbonyl Bond
Addition Reagents and Products:
HCN: Generates cyanohydrins; base catalyst required to generate strong CN − \text{CN}^- CN − nucleophile.
NaHSO 3 \text{NaHSO}_3 NaHSO 3 : Bisulphite addition compound (crystalline solid used for aldehyde separation and purification).
Alcohols: Aldehydes react with 1 eq. ROH / dry HCl 1\text{ eq. ROH} / \text{dry HCl} 1 eq. ROH / dry HCl to form hemiacetals, and 2 eq. ROH 2\text{ eq. ROH} 2 eq. ROH to yield acetals. Ketones react with ethylene glycol to form cyclic ketals.
Ammonia Derivatives (H 2 N-Z \text{H}_2\text{N-Z} H 2 N-Z ):
Hydroxylamine (NH 2 OH \text{NH}_2\text{OH} NH 2 OH ) ⟶ \longrightarrow ⟶ Oxime
Hydrazine (NH 2 NH 2 \text{NH}_2\text{NH}_2 NH 2 NH 2 ) ⟶ \longrightarrow ⟶ Hydrazone
2,4-Dinitrophenylhydrazine (2,4-DNP) ⟶ \longrightarrow ⟶ 2,4-DNP hydrazone (orange-red crystalline precipitate)
Semicarbazide (H 2 NNHCONH 2 \text{H}_2\text{NNHCONH}_2 H 2 NNHCONH 2 ) ⟶ \longrightarrow ⟶ Semicarbazone
6. Condensation Pathways: Aldol vs Cannizzaro
The Carbonyl Fork: Aldol Condensation vs Cannizzaro Reaction
Carbonyl Precursor
Does it possess an
α-Hydrogen?
YES (dil. NaOH)
Aldol Condensation Pathway
Enolate Carbanion → β-Hydroxyaldehyde → α,β-Enone
NO (conc. KOH)
Cannizzaro Disproportionation
Hydride (H⁻) Transfer → 1° Alcohol + Carboxylate Salt
Figure 17.3: Structural Divergence Based on Alpha-Hydrogen Presence in Carbonyl Substrates
Aldol Condensation (≥ 1 α -Hydrogen \ge 1\ \alpha\text{-Hydrogen} ≥ 1 α -Hydrogen ):
Driven by resonance stabilization of the conjugate enolate carbanion in dilute alkali:
2 CH 3 CHO → dil. NaOH CH 3 − CH(OH) − CH 2 − CHO → Δ − H 2 O CH 3 − CH = CH − CHO ( But-2-enal ) 2\text{CH}_3\text{CHO} \xrightarrow{\text{dil. NaOH}} \text{CH}_3-\text{CH(OH)}-\text{CH}_2-\text{CHO} \xrightarrow[\Delta]{-\text{H}_2\text{O}} \text{CH}_3-\text{CH}=\text{CH}-\text{CHO}\quad (\text{But-2-enal})
2 CH 3 CHO dil. NaOH CH 3 − CH(OH) − CH 2 − CHO − H 2 O Δ CH 3 − CH = CH − CHO ( But-2-enal )
Cannizzaro Reaction (No α -Hydrogens \alpha\text{-Hydrogens} α -Hydrogens ):
Disproportionation of aldehydes lacking α \alpha α -hydrogens (HCHO , C 6 H 5 CHO , ( CH 3 ) 3 C-CHO \text{HCHO}, \text{C}_6\text{H}_5\text{CHO}, (\text{CH}_3)_3\text{C-CHO} HCHO , C 6 H 5 CHO , ( CH 3 ) 3 C-CHO ) in concentrated base:
2 C 6 H 5 CHO + conc. NaOH ⟶ C 6 H 5 CH 2 OH ( Benzyl alcohol ) + C 6 H 5 COONa ( Sodium benzoate ) 2\text{C}_6\text{H}_5\text{CHO} + \text{conc. NaOH} \longrightarrow \text{C}_6\text{H}_5\text{CH}_2\text{OH}\ (\text{Benzyl alcohol}) + \text{C}_6\text{H}_5\text{COONa}\ (\text{Sodium benzoate})
2 C 6 H 5 CHO + conc. NaOH ⟶ C 6 H 5 CH 2 OH ( Benzyl alcohol ) + C 6 H 5 COONa ( Sodium benzoate )
Oxidation Tests to Distinguish Aldehydes & Ketones:
Tollens' Test: Aldehydes reduce ammoniacal silver nitrate to form a silver mirror:
R-CHO + 2 [ Ag(NH 3 ) 2 ] + + 3 OH − ⟶ R-COO − + 2 Ag ↓ + 4 NH 3 + 2 H 2 O \text{R-CHO} + 2[\text{Ag(NH}_3)_2]^+ + 3\text{OH}^- \longrightarrow \text{R-COO}^- + 2\text{Ag}\downarrow + 4\text{NH}_3 + 2\text{H}_2\text{O}
R-CHO + 2 [ Ag(NH 3 ) 2 ] + + 3 OH − ⟶ R-COO − + 2 Ag ↓ + 4 NH 3 + 2 H 2 O
Fehling's Test: Aliphatic aldehydes reduce alkaline cupric bistartrate to a red-brown cuprous oxide precipitate (Cu 2 O \text{Cu}_2\text{O} Cu 2 O ); aromatic aldehydes do not react.
Iodoform Reaction: Methyl ketones (RCOCH 3 \text{RCOCH}_3 RCOCH 3 ) and secondary methyl carbinols react with I 2 / NaOH \text{I}_2 / \text{NaOH} I 2 / NaOH to yield a canary-yellow precipitate of iodoform (CHI 3 \text{CHI}_3 CHI 3 ).
7. Carboxylic Acids: Acidity Hierarchy & HVZ Reaction
Resonance Stabilization of Carboxylate: The conjugate base is stabilized by two equivalent resonance structures placing negative charge exclusively on electronegative oxygens.
Substituent Effects on Acidity:
Electron-withdrawing groups (− I , − M -I, -M − I , − M ) disperse negative charge and increase acidity.
Decreasing acidity order:
CF 3 COOH > CCl 3 COOH > CHCl 2 COOH > NO 2 CH 2 COOH > FCH 2 COOH > ClCH 2 COOH > HCOOH > CH 3 COOH \text{CF}_3\text{COOH} > \text{CCl}_3\text{COOH} > \text{CHCl}_2\text{COOH} > \text{NO}_2\text{CH}_2\text{COOH} > \text{FCH}_2\text{COOH} > \text{ClCH}_2\text{COOH} > \text{HCOOH} > \text{CH}_3\text{COOH}
CF 3 COOH > CCl 3 COOH > CHCl 2 COOH > NO 2 CH 2 COOH > FCH 2 COOH > ClCH 2 COOH > HCOOH > CH 3 COOH
Hell-Volhard-Zelinsky (HVZ) Reaction: Carboxylic acids with α \alpha α -hydrogens react with chlorine or bromine in the presence of red phosphorus to form α \alpha α -halocarboxylic acids:
R-CH 2 − COOH → (ii) H 2 O (i) X 2 / Red P R-CH(X)-COOH ( X = Cl, Br ) \text{R-CH}_2-\text{COOH} \xrightarrow[\text{(ii) }\text{H}_2\text{O}]{\text{(i) }\text{X}_2 / \text{Red P}} \text{R-CH(X)-COOH} \quad (\text{X} = \text{Cl, Br})
R-CH 2 − COOH (i) X 2 / Red P (ii) H 2 O R-CH(X)-COOH ( X = Cl, Br )
Decarboxylation: Heating sodium carboxylates with soda-lime (NaOH + CaO \text{NaOH} + \text{CaO} NaOH + CaO in 3 : 1 3:1 3 : 1 ratio) eliminates carbon dioxide to yield an alkane with one less carbon atom:
R-COONa + NaOH → Δ CaO R-H + Na 2 CO 3 \text{R-COONa} + \text{NaOH} \xrightarrow[\Delta]{\text{CaO}} \text{R-H} + \text{Na}_2\text{CO}_3
R-COONa + NaOH CaO Δ R-H + Na 2 CO 3