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Chemical Thermodynamics

Physical Chemistry Weightage: 2–3 Questions (8–12 Marks) NMC Unit 4
“Thermodynamics governs whether a transformation is physically permitted by the universe. From Joule's mechanical equivalence and Hess's state functions to the entropy arrow and Gibbs energy minimization, mastering sign conventions and spontaneity conditions delivers 8 to 12 marks on the NEET paper.”
— SCORECHEM ACADEMIC TEAM

1. Basic Thermodynamic Terms & System Classifications

2. First Law of Thermodynamics, Work & Heat

⚠️ NEET Trap: Work in Expansion vs Compression Under isothermal conditions, reversible expansion extracts maximum work from the system. Conversely, reversible compression requires the minimum work to be performed on the system.

3. Enthalpy ($H$) & Gaseous Phase Reactions

Enthalpy represents total heat content at constant pressure:

ΔH=qp\Delta H = q_p

At constant volume, ΔV=0  ⟹  w=0\Delta V = 0 \implies w = 0, giving ΔU=qv\Delta U = q_v.

4. Heat Capacity ($C$) & Mayer's Relation

5. Thermochemistry, Hess's Law & Standard Enthalpies

6. Entropy ($S$) & The Second Law of Thermodynamics

Entropy quantifies microscopic disorder or thermal randomness. It is a state function:

ΔS=qrevT(Units: J K−1 mol−1)\Delta S = \frac{q_{\text{rev}}}{T} \quad (\text{Units: }\text{J K}^{-1}\text{ mol}^{-1})

7. Gibbs Free Energy ($G$) & Chemical Equilibrium

Gibbs energy defines maximum net work extractable from a system under constant temperature and pressure:

G=H−TS  ⟹  ΔG=ΔH−TΔSG = H - TS \quad \implies \quad \Delta G = \Delta H - T\Delta S

Spontaneity Truth Table

ΔrH\Delta_r H ΔrS\Delta_r S ΔrG\Delta_r G Spontaneity Outcome
−- (Exothermic) ++ (Disordered) −- at all TT Spontaneous at all temperatures
−- (Exothermic) −- (Ordered) −- at low TT; ++ at high TT Spontaneous at low TT only
++ (Endothermic) ++ (Disordered) ++ at low TT; −- at high TT Spontaneous at high TT only
++ (Endothermic) −- (Ordered) ++ at all TT Non-spontaneous at all temperatures

Equilibrium Constant Link

ΔrG∘=−RTln⁡K=−2.303RTlog⁡K\Delta_r G^\circ = -RT \ln K = -2.303 RT \log K

At dynamic equilibrium: ΔrG=0\Delta_r G = 0 and Teq=ΔH∘ΔS∘T_{\text{eq}} = \frac{\Delta H^\circ}{\Delta S^\circ}.