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Solutions

Physical Chemistry Weightage: 2–3 Questions (8–12 Marks) NMC Unit 5
“Liquid solutions form the chemical medium of human physiology and industrial chemistry. From deep-sea divers avoiding the bends with helium mixtures to osmotic pressure preventing hemolysis in red blood cells, mastering Raoult's law, colligative properties, and van 't Hoff factors delivers 8 to 12 marks in NEET.”
— SCORECHEM ACADEMIC TEAM

1. Types of Solutions & Quantitative Concentration Units

Temperature-Independent Units (Mass-Based)

  1. Mass Percentage (% w/w\% \text{ w/w}):

    Mass %=Mass of component in solutionTotal mass of solution×100\text{Mass } \% = \frac{\text{Mass of component in solution}}{\text{Total mass of solution}} \times 100

  2. Parts Per Million (ppm): Useful when solute is present in trace amounts (e.g., fluoride ions in drinking water at 1.0 ppm1.0\text{ ppm} prevents tooth decay; 1.5 ppm1.5\text{ ppm} causes enamel mottling; high levels are toxic):

    ppm=Number of parts of componentTotal parts of all components×106\text{ppm} = \frac{\text{Number of parts of component}}{\text{Total parts of all components}} \times 10^6

  3. Mole Fraction (xx): Dimensionless ratio of moles of a component to total moles in solution. For a binary system of components 1 and 2:

    x1=n1n1+n2,x2=n2n1+n2,x1+x2=1x_1 = \frac{n_1}{n_1 + n_2}, \quad x_2 = \frac{n_2}{n_1 + n_2}, \quad x_1 + x_2 = 1

  4. Molality (mm): Number of moles of solute dissolved per kilogram (1000 g1000\text{ g}) of pure solvent:

    m=nsoluteWsolvent (kg)=w2×1000M2×w1 (g)m = \frac{n_{\text{solute}}}{W_{\text{solvent (kg)}}} = \frac{w_2 \times 1000}{M_2 \times w_1\text{ (g)}}

Temperature-Dependent Units (Volume-Based)

  1. Molarity (MM): Number of moles of solute dissolved per litre (1 dm31\text{ dm}^3) of total solution:

    M=nsoluteVsolution (L)=w2×1000M2×V (mL)M = \frac{n_{\text{solute}}}{V_{\text{solution (L)}}} = \frac{w_2 \times 1000}{M_2 \times V\text{ (mL)}}

  2. Conversion from Molarity to Molality:

    m=1000×M(1000×d)−(M×M2)m = \frac{1000 \times M}{(1000 \times d) - (M \times M_2)}

    Where dd is solution density in g mL−1\text{g mL}^{-1} and M2M_2 is solute molar mass.
⚠️ NEET Trap: Temperature Dependence When heated, the volume of a liquid expands ($V \uparrow$). Consequently, molarity decreases with rising temperature. Molality, mole fraction, and mass percent remain unchanged.

2. Solubility of Gases & Henry's Law Mechanics

Solubility of a gas in a liquid is governed by pressure and temperature.

Biological & Industrial Applications

  1. Soft Drinks: Carbonated beverage bottles are sealed under high pressure to increase CO2CO_2 solubility.
  2. Scuba Diving: Under high hydrostatic pressure deep underwater, N2N_2 dissolves in blood. During rapid ascent, N2N_2 forms gas bubbles in capillaries, causing decompression sickness ("the bends"). Diving cylinders use helium dilution (11.7% He, 56.2% N2N_2, 32.1% O2O_2) because He has very low solubility.
  3. Anoxia: At high altitudes, low atmospheric partial pressure of O2O_2 leads to reduced oxygen levels in blood, producing fatigue and cognitive impairment (anoxia).

3. Vapour Pressure of Liquid Solutions & Raoult's Law

4. Ideal vs Non-Ideal Solutions & Azeotropes

Thermodynamic Property Ideal Solutions Non-Ideal (Positive Deviation) Non-Ideal (Negative Deviation)
Intermolecular Forces A−B≈A−A≈B−BA-B \approx A-A \approx B-B A−B<A−AA-B < A-A or B−BB-B (weaker) A−B>A−AA-B > A-A or B−BB-B (stronger)
Raoult's Law pi=pi∘xip_i = p_i^\circ x_i across all ranges pi>pi∘xip_i > p_i^\circ x_i (pobs>pcalcp_{\text{obs}} > p_{\text{calc}}) pi<pi∘xip_i < p_i^\circ x_i (pobs<pcalcp_{\text{obs}} < p_{\text{calc}})
Enthalpy of Mixing ΔmixH=0\Delta_{\text{mix}} H = 0 ΔmixH>0\Delta_{\text{mix}} H > 0 (Endothermic) ΔmixH<0\Delta_{\text{mix}} H < 0 (Exothermic)
Volume of Mixing ΔmixV=0\Delta_{\text{mix}} V = 0 ΔmixV>0\Delta_{\text{mix}} V > 0 (Expansion) ΔmixV<0\Delta_{\text{mix}} V < 0 (Contraction)
Azeotrope Type No azeotrope formed Minimum boiling azeotrope Maximum boiling azeotrope
High-Yield Examples Benzene + Toluene; nn-hexane + nn-heptane; Bromoethane + Chloroethane Ethanol + Acetone; Acetone + CS2CS_2; Ethanol + Water Chloroform + Acetone; Phenol + Aniline; HNO3HNO_3 + Water

5. Colligative Properties: RLVP, Boiling Elevation & Freezing Depression

Colligative properties depend exclusively on the number of solute particles relative to the total number of particles in solution, independent of their chemical nature.

1. Relative Lowering of Vapour Pressure (RLVP)

p1∘−p1p1∘=x2=n2n1+n2\frac{p_1^\circ - p_1}{p_1^\circ} = x_2 = \frac{n_2}{n_1 + n_2}

For dilute solutions (n2≪n1n_2 \ll n_1):

p1∘−p1p1∘=w2×M1M2×w1\frac{p_1^\circ - p_1}{p_1^\circ} = \frac{w_2 \times M_1}{M_2 \times w_1}

2. Elevation of Boiling Point (ΔTb\Delta T_b)

Addition of a non-volatile solute lowers the solvent's vapour pressure, requiring a higher temperature to match external atmospheric pressure:

ΔTb=Tb−Tb∘=Kb⋅m=1000⋅Kb⋅w2M2⋅w1\Delta T_b = T_b - T_b^\circ = K_b \cdot m = \frac{1000 \cdot K_b \cdot w_2}{M_2 \cdot w_1}

Where KbK_b is the Molal Elevation Constant (Ebullioscopic Constant), measured in K kg mol−1\text{K kg mol}^{-1}. For water, Kb=0.52 K kg mol−1K_b = 0.52\text{ K kg mol}^{-1}.

3. Depression of Freezing Point (ΔTf\Delta T_f)

A solution freezes when its vapour pressure equals that of the pure solid solvent:

ΔTf=Tf∘−Tf=Kf⋅m=1000⋅Kf⋅w2M2⋅w1\Delta T_f = T_f^\circ - T_f = K_f \cdot m = \frac{1000 \cdot K_f \cdot w_2}{M_2 \cdot w_1}

Where KfK_f is the Molal Depression Constant (Cryoscopic Constant). For water, Kf=1.86 K kg mol−1K_f = 1.86\text{ K kg mol}^{-1}.

6. Osmosis, Osmotic Pressure & Desalination

7. Abnormal Molar Mass & The van 't Hoff Factor ($i$)

When a solute undergoes ionic dissociation or molecular association in solution, measured colligative properties deviate from calculated values.

van ’t Hoff Factor (i)=Normal (calculated) molar massAbnormal (observed) molar mass=Observed colligative propertyCalculated colligative property=Total particles after changeTotal particles before change\text{van 't Hoff Factor } (i) = \frac{\text{Normal (calculated) molar mass}}{\text{Abnormal (observed) molar mass}} = \frac{\text{Observed colligative property}}{\text{Calculated colligative property}} = \frac{\text{Total particles after change}}{\text{Total particles before change}}

Modified Colligative Equations

  1. RLVP: p1∘−p1p1∘=i⋅x2\frac{p_1^\circ - p_1}{p_1^\circ} = i \cdot x_2
  2. Boiling Point Elevation: ΔTb=i⋅Kb⋅m\Delta T_b = i \cdot K_b \cdot m
  3. Freezing Point Depression: ΔTf=i⋅Kf⋅m\Delta T_f = i \cdot K_f \cdot m
  4. Osmotic Pressure: Π=i⋅CRT\Pi = i \cdot C R T

Degree of Dissociation (α\alpha) and Association (α\alpha)