Hydrocarbons: Alkanes, Alkenes, Alkynes & Aromatic Compounds
Organic
Weightage: 4-5 Questions (16-20 Marks)
JEE Unit 15
“This is the biggest single unit in JEE organic chemistry because it is really four units folded into one — alkanes, alkenes, alkynes, and aromatic hydrocarbons each get their own preparation methods, reactions, and exam traps, and GOC (Unit 14) is assumed knowledge throughout: electromeric effect, hyperconjugation, carbocation/carbanion/radical stability and electrophilic/nucleophilic language are used here without re-explanation. The throughline worth holding onto is that almost every reaction in this unit is decided by which intermediate forms (carbocation, bridged ion, free radical, or arenium ion) and which stability rule governs that intermediate — learn the mechanism, not just the product.”
— SCORECHEM ACADEMIC TEAM
1. Classification, Isomerism and Nomenclature
- Classification by saturation: alkanes (CnH2n+2, all C–C single bonds, saturated) vs alkenes (CnH2n, one C=C, DU = 1) vs alkynes (CnH2n−2, one C≡C, DU = 2) vs aromatic hydrocarbons (benzene ring, DU = 4 per ring: 1 for the ring + 3 for the three formal double bonds).
- Hybridization fixes geometry directly: alkane carbon is sp3 (tetrahedral, 109.5°); alkene carbon is sp2 (planar, ~120°, with the 121.2° vs 117.2° split in ethene arising because double-bond–single-bond repulsion exceeds single-bond–single-bond repulsion); alkyne carbon is sp (linear, 180°).
- Bond parameters scale together: as hybridization moves sp3 → sp2 → sp, %s-character rises (25% → 33.3% → 50%), bond length falls (1.54 Å → 1.34 Å → 1.20 Å), and bond energy rises (415 → 615 → 835 kJ/mol) — more s-character pulls bonding electrons closer to the nucleus, shortening and strengthening the bond.
- Isomerism specific to this unit: geometrical (cis-trans/E-Z) isomerism needs a C=C (or ring) with two different groups on each restricted carbon — alkynes CANNOT show this at all, since the sp carbon's strict 180° linearity leaves no second spatial arrangement possible around the triple bond.
- Nomenclature essentials: longest chain through the multiple bond gets lowest locant to the multiple bond itself; a ring is named as a prefix (cyclo-) or, for benzene derivatives, substituent positions are numbered to give the lowest locant set, with common names (toluene, xylene, cumene, styrene) still expected at JEE level alongside IUPAC names.
⚠️ JEE Trap: Alkynes show zero geometrical isomerism around the triple bond, full stop. A question describing "cis/trans isomers of an internal alkyne" is testing whether you catch that sp-hybridized, 180°-linear carbons leave no room for any such isomerism to exist — there's no second spatial arrangement to compare against.
2. Alkanes: Conformational Analysis
Fig. 1: Ethane's barrier is PURELY torsional (~12.5 kJ/mol, same at every eclipsed position since all three H's are identical) — unlike n-butane, there is no extra steric contribution because no conformer has two bulky groups unusually close.
- Newman projection: view directly down a C–C bond; the front carbon's three bonds are drawn from a central point, the back carbon's three bonds from behind a circle. Sawhorse projection: a 3-D side-on view along the same axis, showing both carbons offset diagonally — same information, different drawing convention, and JEE questions can mix the two freely.
- Ethane's torsional barrier is PURELY torsional: since all three hydrogens on each carbon are identical, there is no steric difference between any of the three staggered (or three eclipsed) positions — the barrier (~12.5 kJ/mol) comes entirely from eclipsing-bond electron repulsion, not from bulky groups being close together.
- n-Butane adds a steric contribution on top: because the two methyl groups are bulky and distinguishable from the four hydrogens, n-butane's three staggered conformers are no longer equal energy (anti, with methyls 180° apart, is lowest; gauche, with methyls 60° apart, is higher due to steric clash) and its two eclipsed conformers also differ (methyl-over-methyl eclipsing is far worse than methyl-over-H).
- Population at room temperature: the staggered conformers are energy minima and are far more heavily populated than the eclipsed conformers (energy maxima / rotational transition states) at any instant — conformers interconvert freely by bond rotation and are never isolable as separate compounds.
⚠️ JEE Trap: Don't import n-butane's staggered-conformer energy differences into an ethane question. Ethane's three staggered forms are exactly equal in energy (no bulky substituents to distinguish them) — the "anti is most stable" language only becomes meaningful once there are two different kinds of substituents on the two carbons, as in n-butane.
3. Alkanes: Methods of Preparation
- Catalytic hydrogenation of alkenes/alkynes: H2 over Ni/Pt/Pd at 25°C; heterogeneous (two-phase, finely divided metal) hydrogenation is a strict SYN addition — cis-alkene + syn addition gives a meso product, trans-alkene + syn addition gives a racemic pair, when the resulting alkane has two new stereocentres.
- Wurtz reaction: 2 R–X + 2 Na (dry ether) → R–R + 2 NaX, coupling via either an ionic (R− carbanion attacking R–X by SN2) or free-radical pathway. Limited to 1°/2° halides (3° gives E2 elimination instead); mixing two different alkyl halides gives an inseparable mixture of three alkanes (R–R, R–R′, R′–R′); methane CANNOT be made this way (needs at least two fragments to couple); moisture destroys the organosodium intermediate, giving R–H instead of R–R.
- Reduction of alkyl halides: metal/acid (Zn/HCl, Zn–Cu couple, etc.) or metal hydride — LiAlH4 reduces 1°/2° R–X by SN2 but ELIMINATES 3° R–X (strong base → E2) instead of reducing it; NaBH4 is poor/unreactive with 1° R–X but reduces 2°/3°.
- Organometallic routes: Grignard reagents (RMgX) react with ANY active-hydrogen compound (H2O, ROH, NH3, terminal alkynes, RCOOH, RSH) to give R–H, which is why Grignard reactions must be run under strictly anhydrous conditions. Corey-House synthesis (R–X → R–Li → R2CuLi, then + R′–X) is the preferred route to unsymmetrical alkanes: Gilman's reagent tolerates –NO2, –CN, and >C=O groups that would destroy a Grignard reagent, and works best when R′–X is 1°.
- From carboxylic acids: decarboxylation with soda lime (R–COONa + NaOH → R–H + Na2CO3, CaO/Δ) loses one carbon; Kolbe's electrolysis (2 RCOOK + 2 H2O → R–R at the anode) gives an alkane with DOUBLE the carbons of one acid fragment via a radical coupling mechanism (RCOO• → R• + CO2, then R• + R• → R–R).
- Reduction of carbonyl compounds: Clemmensen (Zn–Hg/conc. HCl) and Wolff-Kishner (NH2NH2/KOH) both convert >C=O to >CH2, but Clemmensen fails on acid-sensitive groups (–OH, –NH2, C=C) while Wolff-Kishner fails on base-sensitive groups (–X, esters) — the choice between them is dictated entirely by what ELSE is on the molecule.
⚠️ JEE Trap: Grignard reagents destroy –NO2, –CN and >C=O groups; Gilman's reagent (Corey-House) does not. A synthesis question with a nitro or carbonyl group elsewhere on the molecule is testing whether you reach for Corey-House instead of a Grignard route.
4. Alkanes: Halogenation, Selectivity and Other Reactions
Fig. 2: Both halogens attack 3° C–H fastest per bond (radical stability: 3° > 2° > 1°), but bromine's much larger rate spread makes it highly SELECTIVE while chlorine's narrow spread means the statistical number of H atoms (probability factor) competes with reactivity.
- Free-radical chain mechanism (R–H + X2, UV/heat): Initiation (X2 → 2 X•, endothermic homolysis) → Propagation (X• + R–H → R• + HX, the rate-determining H-abstraction step, then R• + X2 → R–X + X•) → Termination (any two radicals combine). Reactivity of halogens: F2 > Cl2 > Br2 > I2 (F2 is explosive even in the dark; I2 is endothermic/reversible and needs an oxidiser like HIO3 to destroy the HI byproduct and pull the equilibrium forward).
- Selectivity vs reactivity: product yield depends on BOTH the probability factor (number of equivalent H atoms) and the inherent C–H reactivity (3° > 2° > 1° > CH4, tracking radical stability). Chlorination's narrow rate spread (1 : 3.8 : 5.0) makes it low-selectivity — the statistical count of H atoms competes heavily with intrinsic reactivity, giving messy product mixtures. Bromination's huge rate spread (1 : 82 : 1600) makes it highly selective for the 3° position, often >99% yield there even when 3° hydrogens are a small minority of the total.
- Why Cl2 → 2 Cl• initiates (not CH4 → CH3• + H•): the Cl–Cl bond dissociation energy (~58 kcal/mol) is far lower than a C–H bond in methane (~104 kcal/mol), so homolysing the halogen is thermally the much easier first step.
- Other reactions: sulphonation (C≥6 alkanes + oleum/SO3, 400°C → alkanesulphonic acid); isomerization (straight-chain → branched, anhyd. AlCl3/HCl, 300°C); aromatization/reforming (C6–8 alkanes dehydrogenate + cyclize over Cr2O3/Al2O3, 600°C, high pressure → benzene/alkylbenzenes); pyrolysis/cracking (thermal C–C and C–H bond breaking, 400–500°C, no air → smaller alkanes + alkenes + H2).
- Octane number: more branched alkanes have a LOWER heat of combustion (more stable, thermodynamically) and a HIGHER octane number (better anti-knock performance) — iso-octane (2,2,4-trimethylpentane) is fixed at 100, n-heptane at 0.
⚠️ JEE Trap: Chlorination is low-selectivity, bromination is high-selectivity — don't swap them. A "% yield of each monochlorinated product" calculation needs BOTH the number of equivalent hydrogens AND the relative rate per hydrogen; a "which position does bromination favour" question can usually be answered by the 3° position alone, since its huge rate advantage swamps the probability factor.
5. Alkenes: Structure, Stability and Preparation
Fig. 3: Heat of hydrogenation DECREASES as substitution increases — isobutene (disubstituted, 6 alpha-H on one carbon) edges out even trans-2-butene, confirming hyperconjugative stabilisation can outweigh simple substitution count.
- Stability order (substitution rule): tetrasubstituted > trisubstituted > disubstituted > monosubstituted > unsubstituted, driven by hyperconjugation (more alpha-H on the substituents) and homoconjugative resonance. Among disubstituted alkenes specifically, trans > cis (less steric strain between the two substituents) — but isobutene (CH2=C(CH3)2, 6 alpha-H concentrated on ONE carbon) is slightly MORE stable than trans-2-butene, a tested exception to plain substitution-counting.
- Heat of hydrogenation (ΔHhyd) measures stability INVERSELY: ΔHhyd ∝ 1/stability for isomeric alkenes — a LOWER heat of hydrogenation means the alkene started at a LOWER (more stable) energy level before being hydrogenated down to the same final alkane.
- Preparation of alkenes: partial hydrogenation of alkynes via Lindlar's catalyst (H2, Pd/CaCO3 + Pb(OAc)2/quinoline, syn addition → cis-alkene) or Birch reduction (Na/Li in liquid NH3, anti addition via radical-anion → trans-alkene; FAILS for terminal alkynes since the acidic H reacts with Na to form a sodium salt instead); dehalogenation of vicinal dihalides (Zn or NaI); dehydrohalogenation of alkyl halides (E2, alc. KOH, Saytzeff's rule unless a bulky base gives Hofmann product); dehydration of alcohols (conc. H2SO4/160°C or H3PO4, E1 via a carbocation — watch for rearrangement).
⚠️ JEE Trap: More substituted alkene = MORE stable = LOWER heat of hydrogenation, never higher. This is the single most common inversion trap in alkene-stability questions — re-derive the direction from "ΔHhyd measures energy released FROM the alkene," not from memory alone.
6. Alkenes: Electrophilic Addition Mechanisms
Fig. 4: Same alkene, same HBr — the ONLY variable is peroxide. Ionic (Markovnikov) goes through a carbocation; radical (Kharasch) goes through a free radical, and each intermediate's own stability rule decides where X ends up.
- General EAR mechanism: Step 1 (RDS) — the alkene's loosely-held pi electrons attack an electrophile, generating a carbocation or a cyclic bridged ion; Step 2 (fast) — a nucleophile attacks that intermediate to complete addition. Electron-releasing groups on the alkene (+M, +I) speed up Step 1.
- Halogenation (X2): goes through a cyclic halonium ion, NOT a free carbocation — so there is no rearrangement, and addition is strictly ANTI (cis-alkene + Br2 → dl-pair; trans-alkene + Br2 → meso compound, when applicable).
- Markovnikov addition of HX (no peroxide): H⊕ adds to the carbon that already has more hydrogens, generating the MORE stable carbocation (this is the actual mechanistic reason for "Markovnikov's rule," not just a memorised pattern) — the resulting carbocation is prone to 1,2-hydride/methyl shifts toward an even more stable cation before X⊖ attacks.
- Kharasch (peroxide) effect: exclusively for HBr + peroxide (R–O–O–R) + light. RO• abstracts H from HBr to generate Br•, which then adds FIRST to the terminal carbon (forming the more stable secondary/tertiary radical), giving the anti-Markovnikov product. HF and HCl bonds are too strong for the second propagation step; HI's weak bond lets iodine radicals recombine to I2 before they can add — so only HBr shows this effect.
- Hydration, three ways (see the comparison table in the diagram): acid-catalyzed hydration goes through a free carbocation (Markovnikov, non-stereoselective, CAN rearrange); oxymercuration-demercuration goes through a bridged mercurinium ion (Markovnikov, anti-addition, no rearrangement); hydroboration-oxidation goes through a concerted four-centred transition state (anti-Markovnikov, syn-addition, no rearrangement).
Fig. 5: Acid-catalyzed hydration is the only one of the three that goes through a free carbocation — which is exactly why it's the only one prone to rearrangement. The other two avoid a free cation entirely via a bridged/concerted intermediate.
⚠️ JEE Trap: "Peroxide effect" means HBr specifically, not "any HX with peroxide." A question describing HCl or HI with peroxide giving an anti-Markovnikov product is testing whether you know the effect is chemically restricted to HBr alone, for reasons rooted in relative bond strengths, not an arbitrary rule.
7. Alkynes: Acidity, Preparation and Reactions
Fig. 6: sp carbon's 50% s-character makes terminal alkynes acidic enough to form acetylide salts with NaNH2/Na — and the same two hydration routes that split alkenes (Markovnikov vs anti-Markovnikov) apply again here, just landing on a carbonyl instead of an alcohol.
- Acidic character of terminal alkynes: the sp carbon's 50% s-character pulls C–H bonding electron density closer to carbon, stabilising the conjugate base (acetylide ion, R–C≡C⊖) — acidity order H–OH > H–OR > H–C≡CR > H–NH2 > H–CH=CH2 > H–CH2CH3. Terminal alkynes react with strong bases (NaNH2 or Na metal) to form acetylide salts, but are NOT acidic enough to react with weaker bases like NaOH.
- Preparation: double dehydrohalogenation of vicinal/geminal dihalides (alc. KOH, then NaNH2/Δ for the second, harder elimination — vinyl halide is unreactive toward the first base alone due to resonance stabilisation of the C–X bond); hydrolysis of carbides (CaC2 + 2 H2O → ethyne; Mg2C3 + 4 H2O → propyne).
- Addition reactions: HX/X2 — 1 mole gives a vinyl halide, 2 moles give a geminal dihalide; HOX — 1 mole gives an α-haloketone (via an enol intermediate), 2 moles give an α,α-dihaloketone. Mercuric-ion catalyzed hydration (HgSO4/dil. H2SO4) follows Markovnikov addition via an enol that tautomerises to a methyl ketone — EXCEPT ethyne itself, which gives acetaldehyde since there's no alkyl group to make "methyl ketone" apply.
- Hydroboration-oxidation of alkynes: terminal alkyne → aldehyde (R–CH2–CHO, anti-Markovnikov); internal alkyne → ketone (R–CH2–CO–R′).
- Cyclic polymerization: 3 molecules of ethyne through a red-hot iron tube at 873 K → benzene (trimerization); 4 molecules with Ni(CN)2 → 1,3,5,7-cyclooctatetraene (tetramerization).
⚠️ JEE Trap: Ethyne is the one terminal alkyne whose Markovnikov hydration does NOT give a methyl ketone. Every other terminal alkyne R–C≡CH gives R–CO–CH3; ethyne itself (R = H) gives CH3CHO (acetaldehyde) — the one tested exception to an otherwise reliable rule.
8. Conjugated Dienes: 1,2- vs 1,4-Addition
- 1,3-Butadiene (CH2=CH–CH=CH2) undergoes electrophilic addition through a delocalised ALLYLIC carbocation that has partial positive charge at BOTH C2 and C4, so nucleophilic attack can occur at either position.
- Low temperature (−80°C): the 1,2-addition product dominates — the Kinetic Control Product (KCP), formed faster because the nucleophile attacks the nearer, more accessible charge centre directly.
- High temperature (40°C): the 1,4-addition product dominates — the Thermodynamic Control Product (TCP), more stable because it retains a MORE substituted internal double bond, and is favoured once there's enough thermal energy to equilibrate back through the allylic cation and let the more stable product accumulate.
- The general principle (kinetic product forms faster at low temperature; thermodynamic product dominates at high temperature or given enough time to equilibrate) recurs across organic chemistry wherever a reaction can revert through a common intermediate — conjugated diene addition is simply its cleanest textbook example.
⚠️ JEE Trap: Kinetic (1,2-) product at LOW temperature, thermodynamic (1,4-) product at HIGH temperature — the direction is easy to flip under exam pressure. Anchor it to the underlying reason: low temperature doesn't supply enough energy to re-equilibrate through the allylic cation, so whichever product forms first (1,2-, the kinetically faster site) is what you're stuck with.
9. Aromatic Hydrocarbons: Structure and Aromaticity
Fig. 7: Neither Kekulé structure alone is real — benzene is a single resonance HYBRID with all six C–C bonds identical (1.39 Å, between a single 1.54 Å and a double 1.34 Å bond), stabilised by ~36 kcal/mol of resonance/delocalisation energy.
- Benzene is a resonance hybrid, not an equilibrium between two Kekulé structures: neither individual Kekulé structure (alternating single/double bonds) is the real molecule — all six C–C bonds are experimentally identical at 1.39 Å, exactly intermediate between a pure single bond (1.54 Å) and a pure double bond (1.34 Å), because the six pi electrons are fully delocalised around the ring.
- Hückel's rule: a ring is aromatic if it is (i) cyclic, (ii) planar, (iii) fully conjugated (every ring atom has a p orbital), and (iv) has exactly (4n+2) pi electrons in that delocalised system (n = 0, 1, 2…). Benzene has n = 1 → 6 pi electrons.
- Resonance/delocalisation energy: the extra stability benzene has compared to a hypothetical "cyclohexatriene" with three isolated double bonds, experimentally measured as roughly 36 kcal/mol via heat-of-hydrogenation comparison — this large stabilisation is exactly why benzene strongly prefers SUBSTITUTION (which preserves the aromatic sextet) over ADDITION (which would destroy it), unlike an ordinary alkene.
- Nomenclature: mono-substituted benzenes often keep common names (toluene = methylbenzene, cumene = isopropylbenzene, styrene = vinylbenzene); di-substituted patterns are ortho (1,2-), meta (1,3-), or para (1,4-); tri- and higher-substituted rings are numbered for the lowest overall locant set.
⚠︑ JEE Trap: Benzene reacting with Br2/CCl4 does NOT decolorize the way an alkene does. Ordinary alkenes decolorize bromine water/CCl4 instantly via addition; benzene's ~36 kcal/mol of resonance stabilisation makes simple addition unfavourable, so benzene needs a catalyst (FeBr3) and gives SUBSTITUTION instead — a key distinguishing test between an alkene and an aromatic ring.
10. Electrophilic Aromatic Substitution and Directing Effects
Fig. 8: Halogens are the one tested exception — they WITHDRAW electron density overall (deactivating, slower reaction than benzene) but still DONATE by resonance at the ortho/para positions specifically, so they deactivate the ring yet remain o/p-directors.
- General EAS mechanism: the ring's pi system attacks an electrophile (E⊕) to form a resonance-stabilised arenium ion (sigma complex, positive charge delocalised onto the ortho/para-related ring carbons but NEVER the ipso carbon itself), then a base removes the proton from the sp3 carbon to restore full aromaticity.
- Nitration: conc. HNO3 + conc. H2SO4 generates the nitronium ion (NO2⊕) electrophile, which attacks the ring.
- Friedel-Crafts alkylation/acylation: R–X or R–COCl with anhydrous AlCl3 (Lewis acid catalyst generates R⊕ or R–CO⊕). FAILS entirely on strongly deactivated rings (nitrobenzene, and other rings bearing –NO2, –CN, –SO3H, or an existing carbonyl/carboxyl group) because the ring is too electron-poor to attack the electrophile; also fails on aniline-type rings (the Lewis acid complexes with the basic –NH2 lone pair instead of activating the catalyst).
- Directing-group logic: activating groups (+R dominant, like –OH/–NH2/–OR, or +I/hyperconjugation alone, like alkyl groups) donate electron density, speeding up substitution and directing to ortho/para (where that extra density concentrates in the arenium-ion resonance structures). Deactivating groups (–R dominant, like –NO2/–CN/–COOH/–SO3H) withdraw electron density, slowing substitution and directing to meta (the one position where the positive arenium charge is NOT placed directly adjacent to the electron-withdrawing group in any resonance structure).
- Halogens are the sole deactivating-yet-o/p-directing exception: strong –I effect withdraws electron density overall (deactivating, slower than benzene itself), but a lone pair on the halogen still donates by resonance (+R) specifically into the ortho/para positions, directing there even though the net reaction is slower.
⚠️ JEE Trap: A nitro group activates towards NUCLEOPHILIC substitution even while deactivating towards electrophilic substitution. The same –M/–I electron-withdrawal that makes the ring electron-poor (bad for an electrophile, hence deactivating for EAS) makes it MORE attractive to an incoming nucleophile — don't assume "deactivating" always means "unreactive," it depends entirely on which kind of reagent is attacking.
11. Laboratory Identification Tests
- Baeyer's reagent (cold dil. alk. KMnO4): detects C=C or C≡C unsaturation — pink colour disappears as a vicinal diol forms.
- Bromine water / Br2 in CCl4: detects C=C or C≡C unsaturation — reddish-brown colour decolorizes via addition (benzene does NOT give this test under ordinary conditions, see Section 9).
- Tollens' reagent (AgNO3 + NH4OH) and ammoniacal cuprous chloride: detect TERMINAL alkynes specifically (not internal alkynes, not alkenes) — white silver acetylide (R–C≡C–Ag↓) or red copper acetylide (R–C≡C–Cu↓) precipitates, since only a terminal alkyne has the acidic C–H needed to form the acetylide salt.
⚠️ JEE Trap: The Tollens'/ammoniacal-CuCl acetylide test is POSITIVE only for a terminal alkyne, never an internal one. An internal alkyne (R–C≡C–R′) has no acidic C–H left to react, so it gives a negative test despite still being an alkyne — this test distinguishes terminal from internal alkynes, not alkynes from alkenes (Baeyer's/bromine water do that instead).
12. How JEE Frames These Questions
- "Identify the product" sequences: work the sequence one arrow at a time, naming the specific intermediate (carbocation vs bridged ion vs radical vs arenium ion) at each step before deciding the regiochemistry/stereochemistry of that step — most wrong answers come from skipping straight to a remembered "rule" without checking which mechanism actually applies here.
- Reactivity-ordering of substituted benzenes (nitration, halogenation, sulphonation): classify each substituent as activating or deactivating first, then rank purely by that electronic effect — a strongly activating group (anisole-type) reacts fastest, a strongly deactivating group (nitrobenzene-type) reacts slowest, regardless of what the electrophile actually is.
- Assertion-reason / two-statement questions on the peroxide effect: always check whether the halogen acid is specifically HBr — if the question substitutes HCl, HF, or HI "with peroxide," the anti-Markovnikov claim is false no matter how the rest of the statement reads.
- Percentage-composition / mass-percent numericals built on a reaction sequence: identify the final product's structure fully (via the reaction sequence) before computing the percentage — the arithmetic itself is routine, the structure identification is where marks are actually lost.
- "Separation method" questions following a reaction that gives two products: match the method to what actually differs between the two products — different boiling points → (fractional) distillation; volatile vs non-volatile → steam distillation; solid sublimes vs doesn't → sublimation.
⚠️ JEE Trap: A multi-step "identify A, B, C" sequence is scored on EVERY intermediate, not just the final product. Draw each intermediate explicitly rather than jumping to the final answer from memory — a single wrong intermediate early in the sequence invalidates every option built on it.
13. Quick Sheet and Checklist
| Concept | Key Fact |
|---|---|
| Hybridization & bond length | sp3 1.54 Å; sp2 1.34 Å; sp 1.20 Å (shorter as s-character rises) |
| Halogen reactivity | F2 > Cl2 > Br2 > I2; Cl2 low selectivity, Br2 high selectivity (3° >> 1°) |
| Markovnikov vs Kharasch | HX (no peroxide) → carbocation → Markovnikov; HBr + peroxide ONLY → radical → anti-Markovnikov |
| Hydration routes | Acid-catalyzed: carbocation, Markovnikov, CAN rearrange. OMDM & HBO: no free cation, no rearrangement (Markovnikov / anti-Markovnikov resp.) |
| Alkyne acidity | pKa ~25; forms acetylide with NaNH2/Na; terminal only |
| Alkyne hydration | HgSO4/H2SO4 → methyl ketone (ethyne → acetaldehyde exception); hydroboration → aldehyde (anti-Mark.) |
| Diene addition | Low T → 1,2- (kinetic); High T → 1,4- (thermodynamic) |
| Aromaticity | Cyclic, planar, fully conjugated, (4n+2) pi electrons (Hückel) |
| EAS directing | Activating (+R/+I) → o/p; deactivating (–R/–I) → m; halogens: deactivating but o/p (exception) |
| Friedel-Crafts limit | Fails on strongly deactivated rings and on aniline-type (–NH2) rings |
| Terminal alkyne test | Tollens'/ammoniacal CuCl → positive for TERMINAL alkynes only |
Before the exam, check you can:
- Explain why alkynes show zero geometrical isomerism, directly from sp hybridization and 180° linearity.
- Distinguish Newman and Sawhorse projections, and explain why ethane's conformers are equal-energy within each type while n-butane's are not.
- State which organometallic route (Grignard vs Corey-House) survives a nitro, cyano, or carbonyl group elsewhere on the molecule, and why.
- Derive (not just recall) why more substituted alkenes have a LOWER heat of hydrogenation despite being MORE stable.
- Name the exact conditions under which the peroxide effect operates (HBr only) and explain mechanistically why HCl/HF/HI don't show it.
- Compare the three hydration methods by intermediate, regiochemistry, stereochemistry, and rearrangement risk.
- State the acidity order of terminal alkynes relative to water, alcohols, and ammonia, and explain it from s-character.
- Predict 1,2- vs 1,4-addition on a conjugated diene from the reaction temperature alone.
- Explain why benzene gives substitution rather than addition, in terms of resonance/delocalisation energy.
- Classify any ring substituent as activating/deactivating and o/p- or m-directing, including the halogen exception.