Classification of Elements and Periodicity in Properties
Inorganic Chemistry
Weightage: 2-3 Questions (8-12 Marks)
JEE Unit 9
“Welcome to Inorganic Chemistry! These notes assume you have already read the NCERT chapter on classification and periodicity, so you know Mendeleev's table, the modern periodic law, s/p/d/f blocks and the basic left-to-right, top-to-bottom trends by name. Here we keep what JEE Main actually asks: assertion-reason statements pairing two trend facts (one usually an exception), ranking three or four elements by radius or ionization energy, and the odd numerical on group-number or bond-length formulas. Learn the master trends matrix and its exceptions below cold — JEE Main loves testing exactly the anomaly, not the rule.”
— SCORECHEM ACADEMIC TEAM
1. From Dobereiner to the Modern Periodic Law
- Dobereiner's triads (1817): in a triad, the middle element's atomic mass ≈ mean of the outer two (Li, Na, K: (7+39)/2 = 23). Worked only for a few sets and failed for F, Cl, Br.
- Newlands' law of octaves (1865): arranged by increasing atomic mass, every 8th element repeated properties. Worked only up to Ca (Z = 20); broke down once transition metals appeared.
- Lothar Meyer's atomic volume curve (1869): atomic volume (mass/density) plotted against atomic mass is periodic. Alkali metals sit at the crests (largest volume); transition metals sit in the troughs (most compact, densest).
- Mendeleev's periodic law (1869): properties are a periodic function of atomic mass. Merits: left gaps that correctly predicted eka-aluminium (Ga) and eka-silicon (Ge); corrected Be's valency from 3 to 2. Demerits: anomalous pairs where a heavier element was placed before a lighter one purely to keep similar properties together (Ar before K, Te before I, Co before Ni), no separate position for isotopes, and no single consistent slot for hydrogen.
- Moseley's experiment (1913): √ν = a(Z−b) for characteristic X-ray frequency ν, proving atomic number (not mass) is the fundamental property. This gives the Modern Periodic Law: properties are a periodic function of atomic number (Z), and periodicity itself arises because valence-shell configurations repeat at regular intervals (e.g. every alkali metal is ns1).
⚠️ JEE Trap: The anomalous-pair reasoning. Ar/K, Te/I and Co/Ni are placed "out of atomic-mass order" in Mendeleev's table specifically so each element lands in the group matching its chemical properties — this was later explained (and resolved) once atomic number replaced atomic mass as the ordering principle.
2. Periods, Blocks and Group-Number Rules
Fig. 1: The four blocks, named for the subshell receiving the last (differentiating) electron.
- Period number = highest principal quantum number (n) in the valence shell. Period 3 has only 8 elements (not 18) because 4s fills before 3d (Aufbau), so the period ends after 3s and 3p are full.
- Block = the subshell receiving the last (differentiating) electron. Group number: s-block = number of valence s-electrons; p-block = 10 + (valence s + p electrons); d-block = (n−1)d electrons + valence ns electrons; f-block is always Group 3 (IIIB).
- Worked pattern 1 (Copernicium, Z = 112): configuration [Rn] 5f14 6d10 7s2. Highest n = 7 ⇒ Period 7. Last electron enters 6d ⇒ d-block. Group = 10 (d) + 2 (s) = Group 12.
- Exceptions in configuration: Cr (Z=24) and Cu (Z=29) are 3d54s1 and 3d104s1 (extra stability of half-filled/fully-filled d); Pd (Z=46) is 4d105s0 (empty 5s); He is 1s2 (s-block by configuration) but placed in Group 18 for its noble-gas chemistry.
⚠️ JEE Trap: Group-number formula direction. The p-block formula adds 10 to (s+p) electrons, not the other way around; a common slip is forgetting the +10 offset and reporting a d-block-style group number for a p-block element.
3. Diagonal Relationship and Special Categories
- Representative (normal) elements: all s- and p-block elements (Groups 1, 2, 13–17), excluding noble gases. Typical elements: the Period 3 set Na–Cl, whose behaviour best represents their group's general chemistry (better than the Period 2 member). Metalloids: B, Si, Ge, As, Sb, Te — border metals and non-metals, with amphoteric oxides.
- Diagonal relationship: Li–Mg, Be–Al and B–Si (2nd period element with the 3rd period element one group to its right) show close chemical similarity, because moving right (size falls) and moving down (size rises) roughly cancel diagonally, keeping ionic radius, electronegativity and ionic potential (φ = charge/radius²) nearly equal (Li+ = 0.76 Å, Mg2+ = 0.72 Å).
- Li & Mg: both form nitrides directly (Li3N, Mg3N2), insoluble fluorides/carbonates/phosphates, and their carbonates decompose on heating. Be & Al: both give amphoteric oxides/hydroxides, go passive in conc. HNO3, form covalent electron-deficient polymeric chlorides (BeCl2, AlCl3), and neither colours a Bunsen flame.
⚠️ JEE Trap: Diagonal pairs go 2nd-period-element to 3rd-period-element ONE GROUP TO THE RIGHT. Li (Group 1) pairs with Mg (Group 2), not with Na (Group 1); Be (Group 2) pairs with Al (Group 13), not with Mg.
4. Atomic Radius, Ionic Radius and Isoelectronic Series
Fig. 4: Period → smaller; group → bigger. Cation always smaller, anion always bigger, than its parent atom.
- Three radius definitions: covalent radius (half the internuclear distance in a homonuclear covalent bond) < metallic/crystal radius < van der Waals radius (half the distance between non-bonded neighbouring atoms, always 40–80% bigger than covalent radius).
- Stevenson–Schomaker (heteronuclear bond length): dA–B = rA + rB − 0.09Δχ (Å), or −9.0Δχ in pm, where Δχ = |χA−χB|. Porterfield's version uses −7.0(Δχ)² (pm).
- Worked pattern 2: C–C = 1.54 Å, X–X = 1.00 Å, χC = 2.0, χX = 3.0. rC = 0.77, rX = 0.50, Δχ = 1.0. dC–X = 0.77 + 0.50 − 0.09(1.0) = 1.18 Å.
- Why noble gases look "largest" in their period: their tabulated radius is a van der Waals radius (no covalent bond to measure), while every other element in that period is measured as a covalent radius — not a genuine anomaly in metallic/covalent size.
- 3d series radius dip-then-flat-then-rise: falls Sc→Cr, stays nearly flat Cr→Cu (d-electron shielding balances rising Z), rises slightly at Zn (inter-electronic repulsion in the filled 3d10).
- Lanthanide contraction: poor shielding by the 14 inner 4f electrons steadily shrinks the lanthanides from Ce to Lu, making the 2nd and 3rd transition series (4d vs 5d) almost the same size (Zr ≈ Hf = 1.60 Å, Nb ≈ Ta = 1.46 Å) despite the extra shell.
- Ions: cation always smaller than its parent atom (higher Zeff per electron, often a whole shell removed: Na 1.86 Å → Na+ 1.02 Å); anion always larger (added inter-electronic repulsion: Cl 0.99 Å → Cl− 1.84 Å).
- Isoelectronic series: same electron count, radius falls as Z rises: N3−(1.71) > O2−(1.40) > F−(1.36) > Na+(1.02) > Mg2+(0.72) > Al3+(0.53 Å).
⚠️ JEE Trap: "Atomic radius is always greater than ionic radius" is FALSE. True only for cations. For an anion, the ionic (anionic) radius is LARGER than the parent atom's radius — a frequently-set false assertion.
5. Ionization Energy
Fig. 5: First ionization energy across Period 2. Two dips break the rising trend: at B (after the stable 2s2 of Be) and at O (after the stable 2p3 of N).
- Definition: M(g) + IE1 → M+(g) + e−; successive IEs always increase, IE1 < IE2 < IE3, since each further electron is removed from an increasingly positive ion.
- Governing factors: IE ∝ 1/(atomic size); IE ∝ Zeff; penetration power order s > p > d > f (so a full ns² or half-filled np³ boosts IE beyond the smooth trend).
- Period 2 anomaly: expected Li < Be < B < C < N < O < F < Ne becomes Li < B < Be < C < O < N < F < Ne. Be > B because Be's filled 2s² resists ionization more than B's lone 2p¹. N > O because N's half-filled 2p³ is extra stable, while O's 2p⁴ already has one paired (repelled) electron that ionizes more easily.
- Period 3 anomaly: Na < Al < Mg < Si < S < P < Cl < Ar, by the same two rules (Mg > Al from filled 3s²; P > S from half-filled 3p³).
- Group 13 irregularity: B > Tl > Ga > Al > In. Ga sits above Al because of poor d-orbital shielding (scandide-like contraction after the 3d row); Tl sits above Ga because of poor f-orbital shielding (lanthanide contraction after the 4f row).
- Second ionization energy pattern: IE2 reflects the stability of M+'s configuration. Na's IE2 is enormous (breaks into the stable, filled 2p⁶ core of Na+) — far larger than Mg's IE2 (removes a normal 3s electron from an already-stable Mg+).
⚠️ JEE Trap: Treat every IE ranking as "apply the anomaly rules first." Any 3–5 element ranking question is testing whether you remember the Be>B / N>O (or Mg>Al / P>S) exceptions — a purely left-to-right guess will get exactly these questions wrong.
6. Electron Gain Enthalpy and Electronegativity
- Definition: X(g) + e− → X−(g), ΔegH ≈ −Ea (electron affinity). First EGA is usually negative (exothermic); second EGA is ALWAYS positive (O− + e− → O2−, ΔegH2 = +744 kJ/mol) because the incoming electron is repelled by the existing negative charge.
- Cl > F, S > O anomaly: the compact n = 2 shell in F and O suffers severe inter-electronic repulsion when accepting one more electron, so the magnitude of ΔegH is actually SMALLER (less negative) for F and O than for the larger n = 3 elements below them: Cl > F > Br > I, and S > Se > Te > Po > O. Oxygen has the least negative EGA in Group 16.
- Noble gases and Group 2: near-zero or positive ΔegH (stable filled configuration, no room to accommodate an extra electron favourably).
- Electronegativity (χ): tendency to attract shared bonding electrons. Pauling's scale uses bond-energy differences; Mulliken's scale χM = ½(IE + EA) in eV, converted to Pauling by χP = χM/2.8.
- % ionic character (Hannay–Smith): 16Δχ + 3.5(Δχ)², where Δχ = χA − χB.
- Electronegativity rises with: % s-character in hybridization (sp > sp² > sp³) and with higher oxidation state (Fe³⁺ > Fe²⁺).
⚠️ JEE Trap: Electron gain enthalpy is a signed quantity; "electron affinity" in older question text is its magnitude. "Cl has higher/more negative EGA than F" and "F has higher electron affinity than Cl" describe DIFFERENT (opposite-sounding but consistent) comparisons only if you keep sign conventions straight — always convert to "magnitude of ΔegH" before comparing across a question's wording.
7. Oxides, Inert Pair Effect and Chemical Periodicity
Fig. 6: Period 3 oxides, left (metal, basic) to right (non-metal, acidic). Basic character falls, acidic character rises, across a period.
- Oxide classes: basic (electropositive metal oxides, form hydroxides; basic character rises down a group: Na2O, K2O, CaO), acidic (non-metal oxides, form oxyacids; acidity rises across a period: CO2, SO3, Cl2O7), amphoteric (metalloids/select metals: BeO, Al2O3, ZnO, SnO, PbO), neutral (CO, NO, N2O, H2O).
- Period 3 oxide strip: Na2O (strongly basic) > MgO (basic) > Al2O3 (amphoteric) > SiO2 (weakly acidic) > P4O10 (acidic) > SO3 (acidic) > Cl2O7 (strongly acidic).
Fig. 3: Inert pair effect — the heaviest member of each group favours the LOWER oxidation state.
- Inert pair effect: the ns² pair in heavier p-block elements (n ≥ 4, Groups 13–15) resists bonding due to poor shielding by intervening d/f electrons, so the LOWER oxidation state becomes progressively more stable going down the group: Group 13, Tl⁺ most stable; Group 14, Pb²⁺ most stable; Group 15, Bi³⁺ most stable.
- Consequences: Pb⁴⁺ and Bi⁵⁺ are strong oxidizers (readily fall back to the stable lower state); PbI4 and BiI5 don't exist (I−'s reducing power destroys the higher oxidation state) — though TlI3 exists, unusually, as Tl+(I3)− rather than as Tl3+(I−)3.
⚠️ JEE Trap: "More stable at a lower oxidation state" does NOT mean the higher state doesn't exist. Pb4+ and Bi5+ compounds do exist; they are simply strong oxidizing agents because they "want" to revert to Pb2+/Bi3+.
8. How JEE Frames Questions
Fig. 2: The master periodic-trends matrix — learn this table, then learn the exceptions.
- Assertion-reason / two-statement MCQs: the dominant format. One statement states a plain trend, the other states an exception (Be > B, N > O, Cl > F, Ga vs Al, etc.) — both need to be checked independently before combining.
- Ranking questions: 3–5 elements ranked by radius, IE, EGA or metallic character — always re-derive using the group/period position and the exception rules, never guess from memory of a similar-looking list.
- Statement-matching (List I / List II): matches a property (highest EN, largest size, metalloid behaviour, most negative EGA) to element pairs; work each property from first principles.
- Formula numericals: bond length (Stevenson–Schomaker/Porterfield), % ionic character, group-number-from-configuration, or an energy calculation combining IE1 and IE2.
⚠️ JEE Trap: Never answer a periodicity ranking from a "rule of thumb" alone. Write out each element's block/group/period first; the anomalies (Be/B, N/O, Mg/Al, P/S, Ga/Al, Tl/Ga) are common enough in JEE Main that a purely smooth left-to-right/top-to-bottom guess is wrong more often than right.
9. Quick Sheet and Checklist
| Idea | Rule |
|---|---|
| Modern periodic law | Property = periodic function of atomic number (Z) |
| Group number (p-block) | 10 + (valence s + p electrons) |
| Radius order | rcovalent < rmetallic < rvdW; cation < atom < anion |
| Bond length (Stevenson–Schomaker) | dA-B = rA + rB − 0.09Δχ (Å) |
| IE anomaly (Period 2) | Li < B < Be < C < O < N < F < Ne |
| EGA anomaly | Cl > F > Br > I; S > Se > Te > Po > O; 2nd EGA always +ve |
| % ionic character | 16Δχ + 3.5(Δχ)² |
| Inert pair effect | lower O.S. more stable down Groups 13–15 (Tl⁺, Pb²⁺, Bi³⁺) |
Before the exam, check you can:
- Assign period, block and group number from an electron configuration, including the +10 p-block offset.
- Reproduce both Period 2 and Period 3 IE anomalies and explain WHY (filled s² / half-filled p³) rather than just memorising the order.
- Rank an isoelectronic series by radius and identify a diagonal-relationship pair correctly.
- State the Cl>F / S>O electron-gain-enthalpy anomaly and why the second EGA is always positive.
- Use the inert-pair effect to predict which oxidation state is more stable/more oxidizing for Tl, Pb, Bi and their lighter group-mates.
- Classify a Period 3 oxide as basic, amphoteric or acidic and rank the whole row.