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Chemical Bonding

Physical Chemistry Weightage: AS · Papers 1 and 2 (assumed in Papers 4 and 5) Topic 3
“Welcome! Bonding is the topic Cambridge uses to test whether you can explain, not just recall. Every ‘explain why’ here has a fixed three-step answer: name the particles, name the force between them, and say why that force is strong or weak. Learn that pattern, draw the diagrams with every lone pair and partial charge, and this topic becomes reliable marks.”
— SCORECHEM ACADEMIC TEAM

0. What Examiners Want

How marks are earned in bonding questions
  • Name the particles and the force. “Strong electrostatic attraction between Mg2+ ions and delocalised electrons” scores; “strong bonds” does not.
  • Compare, then explain. For a difference in melting point, state which force is stronger and why (higher charge, smaller ion, more electrons, more hydrogen bonds).
  • Diagrams have marking points. Lone pairs, partial charges, dotted hydrogen bonds and correct shapes are each credited separately. A missing lone pair loses a mark.
  • Keywords must be used correctly. “Ionic” for NaCl, “metallic” for Mg, “simple molecular” for I2. A correct keyword in the wrong place earns nothing.
  • Do not mix up bond and force. Covalent, ionic and metallic bonds are strong. Hydrogen bonds, pd–pd and id–id are intermolecular forces.

1. Electronegativity and Bond Polarity

Definition to learn word for word: Electronegativity is the ability of an atom to attract the bonding pair of electrons in a covalent bond.

non-polar covalent ionic polar covalent difference in electronegativity increases → Cl–Cl ΔEN = 0 electrons shared equally H–Cl ΔEN = 0.9 shared unequally: Hδ+–Clδ− Na–Cl ΔEN = 2.1 electron transferred: Na+ Cl− Electronegativity: the ability of an atom to attract the bonding pair of electrons in a covalent bond increases across a period (more nuclear charge, similar shielding, smaller radius) decreases down a group (more shells and shielding, larger radius)
Bonding is a continuum. The bigger the difference in electronegativity between the two atoms, the more the bonding pair is pulled towards one atom. A polar bond has partial charges (δ+ and δ−); a symmetrical molecule can have polar bonds and still be non-polar overall (dipoles cancel).

A molecule is polar only if the dipoles do not cancel. CO2, BF3, CH4 and CCl4 have polar bonds but are symmetrical, so the dipoles cancel and the molecule is non-polar. H2O, NH3, HCl and CHCl3 are polar.

⚠️ Examiner Trap: Polar bonds, non-polar molecule. “CO2 has no dipole because C and O have the same electronegativity” is wrong. Each C=O bond is polar; the two dipoles point in opposite directions in a linear molecule, so they cancel.

2. Ionic Bonding

Definition: Ionic bonding is the electrostatic attraction between oppositely charged ions. It happens between a metal (loses electrons) and a non-metal (gains electrons), and the ions are arranged in a giant lattice.

⚠️ Examiner Trap: Which particles carry the current? In molten NaCl the charge carriers are the ions. In a metal they are delocalised electrons. Do not write “free electrons” for an ionic liquid.

3. Metallic Bonding

Definition: Metallic bonding is the electrostatic attraction between the positive metal ions in a lattice and the sea of delocalised electrons.

+ + + + + + + + + + + + + + + + + + + + + + + + positive metal ions in a regular lattice sea of delocalised electrons (mobile) attraction between ions and electrons = metallic bond
Metallic bonding: the electrostatic attraction between the lattice of positive ions and the delocalised electrons. More charge on the ion and more delocalised electrons per atom, with a smaller ion, give a stronger bond and a higher melting point (Al > Mg > Na). The mobile electrons carry charge, so metals conduct when solid.

4. Covalent and Dative Bonding

Covalent bond: the electrostatic attraction between a shared pair of electrons and the nuclei of the two bonded atoms. Dative (coordinate) covalent bond: a shared pair of electrons where both electrons are supplied by the same atom. Once formed it is identical to any other covalent bond. It is shown with an arrow from the donor: NH3 → H+, and H3N → BF3.

Ionic: NaCl Na+ Cl × Cl−: 8 e− Na loses its outer electron (×) to Cl. No electrons shared. Covalent: N2 N N × × × × × 3 shared pairs + 1 lone pair on each N Triple bond: 1 σ + 2 π Each N has 8 electrons Dative: NH4+ N H H × H × H × [ ] dative Dative pair: both e− from N
Dot-and-cross diagrams show outer electrons only. Use dots and crosses to show which atom each electron came from, draw every lone pair, and show the charge with square brackets for an ion. A dative covalent bond is a shared pair in which both electrons come from the same atom.

Drawing dot-and-cross diagrams

  1. Draw only the outer shell of each atom, using dots for one atom's electrons and crosses for the other's.
  2. Put the shared pair(s) in the overlap. A double bond has two shared pairs and a triple bond three.
  3. Show every lone pair. Check each atom has the correct number of electrons: 8 for period 2 atoms (or 2 for H), but some period 3 atoms can have more (PCl5 has 10, SF6 has 12).
  4. For ions, use square brackets with the charge outside.
  5. For a dative bond, use the same symbol for both electrons in the pair (both dots) and mention that both electrons come from the donor.

Sigma and pi bonds. A σ bond is the head-on overlap of orbitals along the bond axis. A π bond is the side-on overlap of two p orbitals, above and below the axis. A single bond is one σ; a double bond is one σ + one π; a triple bond is one σ + two π.

sigma (σ) bond head-on overlap of orbitals along the line between the nuclei s+s, s+p, p+p (end-on), sp²+sp² Every single bond is one σ bond. pi (π) bond side-on overlap of two p orbitals above and below the σ bond axis C=C: one σ + one π C≡C: one σ + two π
In the double bond of ethene, the C atoms use sp² hybrid orbitals for the σ bonds (trigonal planar, 120°) and the unused p orbitals overlap side-on to form the π bond. A π bond is weaker than a σ bond because side-on overlap is less effective, and it stops rotation about the C=C bond.

Bond length and bond energy. Bond energy is the energy needed to break one mole of a bond in the gas phase. As the number of shared pairs between two atoms increases, the bond gets shorter and stronger: C–C (154 pm, 347 kJ mol−1), C=C (134 pm, 612 kJ mol−1), C≡C (120 pm, 838 kJ mol−1). Note that C=C is less than twice C–C because the π component is weaker than a σ bond.

Triple bond strength explains why N2 is unreactive (N≡N is very strong, and the molecule is non-polar).

⚠️ Examiner Trap: Counting σ and π bonds. Count every bond, including C–H. For CH3CH=CHCN: nine σ bonds and three π bonds. A double bond is 1 σ + 1 π, and a triple bond is 1 σ + 2 π; never count a triple bond as three σ bonds.

Electron-deficient molecules. BF3 and AlCl3 have only six electrons around the central atom and an empty p orbital, so they accept a lone pair. That is why NH3 forms H3N→BF3, and why aluminium chloride dimerises to Al2Cl6 (each Al accepts a lone pair from a Cl atom of the other unit, forming dative bonds).

5. Shapes of Molecules and Ions

VSEPR rule: electron pairs around the central atom repel and get as far apart as possible. Lone-pair–lone-pair repulsion > lone-pair–bonding-pair > bonding-pair–bonding-pair, so lone pairs squeeze the bond angle.

Linear 180° BeCl2, CO2 Trigonal planar 120° BF3 Tetrahedral 109.5° CH4 Pyramidal 107° NH3 Bent (V-shaped) 104.5° H2O Trigonal bipyramidal 90° and 120° PCl5 Octahedral 90° SF6 Key in plane towards you away from you lone pair
VSEPR: electron pairs repel and spread as far apart as possible. Count the electron pairs (bonding + lone) around the central atom, then name the shape from the atoms only. Lone pairs repel more than bonding pairs, so each lone pair squeezes the bond angle by about 2.5° (109.5° → 107° → 104.5°).
Electron pairs Lone pairs Shape Angle Example
2 0 Linear 180° BeCl2, CO2
3 0 Trigonal planar 120° BF3, AlCl3
4 0 Tetrahedral 109.5° CH4, NH4+, PCl4+
4 1 Pyramidal 107° NH3, PCl3
4 2 Bent (V-shaped) 104.5° H2O
5 0 Trigonal bipyramidal 90° and 120° PCl5
6 0 Octahedral 90° SF6, PCl6−

Method: (1) find the number of outer electrons on the central atom, add one for each bond it makes and adjust for the ion charge; (2) divide by two to get pairs; (3) subtract bonding pairs to get lone pairs; (4) match the table. A double bond counts as one region of electron density.

⚠️ Examiner Trap: Name the shape, quote the angle. “Tetrahedral” for NH3 loses the mark: the arrangement of pairs is tetrahedral but the shape is pyramidal. Also give the angle as a number, and say why it is less than 109.5° (lone pairs repel more than bonding pairs).

6. Intermolecular Forces

Intermolecular forces (IMFs) act between molecules. They are far weaker than covalent bonds. There are three types.

Covalent bond (inside the molecule) intact when a simple molecule melts Hydrogen bond (H on N, O, F) strongest intermolecular force Permanent dipole–dipole (pd–pd) between polar molecules Instantaneous dipole–induced dipole (id–id) all molecules; grows with number of electrons Relative strength only (bars not to scale).
Ranking the forces. When a simple molecular substance melts or boils, only the intermolecular forces break; the covalent bonds inside the molecules stay intact. Never write “covalent bonds break” for a simple molecular substance melting.
N δ− H H H δ+ hydrogen bond N–H···N in a straight line H δ+ N δ− H H Hydrogen bond needs: (1) H covalently bonded to N, O or F, (2) a lone pair on a different N, O or F atom to attract that H.
Hydrogen bonding between two NH3 molecules, as Cambridge asks it. Show the lone pair on N, the partial charges (δ+ on H, δ− on N), and the dotted line running N–H···N in a straight line.

Water is special. Each water molecule can form up to four hydrogen bonds (two through its two H atoms and two through the two lone pairs on O). This gives water a high melting and boiling point, high surface tension and a high enthalpy of vaporisation. In ice the molecules are held in an open lattice with more space between them, so ice is less dense than liquid water.

150 200 250 300 350 400 boiling point / K period 2 period 3 period 4 period 5 H₂O H₂S H₂Se H₂Te HF HCl HBr HI Group 16 hydrides Group 17 hydrides hydrogen bonding id–id forces rise down the group
Boiling points of the hydrides rise from period 3 to period 5 because id–id forces grow with the number of electrons. H2O and HF are ‘out of line’ because hydrogen bonds between their molecules take extra energy to overcome (this is Paper 1 style reasoning: H2O is a liquid and H2S a gas at room temperature).

Why H2O melts higher than NH3: each H2O molecule can form two hydrogen bonds on average, but NH3 has only one lone pair so forms one, and the O–H···O hydrogen bond is stronger because O is more electronegative than N.

⚠️ Examiner Trap: Is it really hydrogen bonding? CH3F and CH3OCH3 have F or O but no H bonded to it, so no hydrogen bonds form between their own molecules. CH3OH and CH3CH2OH do. Check that the H is attached to N, O or F, not to carbon.

7. Structure and Properties

Type Particles and force Melting point Conducts? Examples
Giant ionic Ions; strong ionic bonding in a lattice High Only molten or aqueous NaCl, MgO
Giant metallic Positive ions in a sea of delocalised electrons High (varies) Solid and liquid Na, Mg, Cu
Giant covalent Atoms; strong covalent bonds throughout Very high No (except graphite) Diamond, SiO2, graphite
Simple molecular Small molecules; weak IMFs between them Low No I2, SiCl4, H2O, CO2

8. Quick Sheet and Checklist

Before you leave this topic, can you:

  1. Draw two NH3 molecules with the hydrogen bond, including lone pairs and partial charges?
  2. Explain why MgO has a much higher melting point than NaCl?
  3. Give the shape and bond angle of H2O and explain why the angle is 104.5°?
  4. Say why graphite conducts electricity but diamond does not?

If yes to all four, attempt the ten exam-style questions with the mark schemes covered, then open the flashcards.